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Message-ID: <20191004154102.GA20945@redhat.com>
Date: Fri, 4 Oct 2019 17:41:03 +0200
From: Oleg Nesterov <oleg@...hat.com>
To: "Joel Fernandes (Google)" <joel@...lfernandes.org>
Cc: linux-kernel@...r.kernel.org, bristot@...hat.com,
peterz@...radead.org, paulmck@...nel.org, rcu@...r.kernel.org,
Josh Triplett <josh@...htriplett.org>,
Lai Jiangshan <jiangshanlai@...il.com>,
Mathieu Desnoyers <mathieu.desnoyers@...icios.com>,
"Paul E. McKenney" <paulmck@...ux.ibm.com>,
Steven Rostedt <rostedt@...dmis.org>
Subject: Re: [PATCH] Remove GP_REPLAY state from rcu_sync
On 10/04, Joel Fernandes (Google) wrote:
>
> But this is not always true if you consider the following events:
I'm afraid I missed your point, but...
> ---------------------->
> GP num 111111 22222222222222222222222222222222233333333
> GP state i e p x r rx i
> CPU0 : rse rsx
> CPU1 : rse rsx
> CPU2 : rse rsx
>
> Here, we had 3 grace periods that elapsed, 1 for the rcu_sync_enter(),
> and 2 for the rcu_sync_exit(s).
But this is fine?
We only need to ensure that we have a full GP pass between the "last"
rcu_sync_exit() and GP_XXX -> GP_IDLE transition.
> However, we had 3 rcu_sync_exit()s, not 2. In other words, the
> rcu_sync_exit() got batched.
>
> So my point here is, rcu_sync_exit() does not really always cause a new
> GP to happen
See above, it should not.
> Then what is the point of the GP_REPLAY state at all if it does not
> always wait for a new GP?
Again, I don't understand... GP_REPLAY ensures that we will have a full GP
before rcu_sync_func() sets GP_IDLE, note that it does another "recursive"
call_rcu() if it sees GP_REPLAY.
> Taking a step back, why did we intend to have
> to wait for a new GP if another rcu_sync_exit() comes while one is still
> in progress?
To ensure that if another CPU sees rcu_sync_is_idle() (GP_IDLE) after you
do rcu_sync_exit(), then it must also see all memory changes you did before
rcu_sync_exit().
Oleg.
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