linux-kernel - drm/mcde: Checking for a failed platform_get_irq() call in mcde

lists.openwall.net		lists / announce owl-users owl-dev john-users john-dev passwdqc-users yescrypt popa3d-users / oss-security kernel-hardening musl sabotage tlsify passwords / crypt-dev xvendor / Bugtraq Full-Disclosure linux-kernel linux-netdev linux-ext4 linux-hardening linux-cve-announce PHC
Open Source and information security mailing list archives

Hash Suite: Windows password security audit tool. GUI, reports in PDF.

[<prev] [next>] [day] [month] [year] [list]

Message-ID: <abd9674c-adf7-b040-814c-076e32a5a48e@web.de>
Date:   Wed, 8 Apr 2020 14:20:28 +0200
From:   Markus Elfring <Markus.Elfring@....de>
To:     dri-devel@...ts.freedesktop.org,
        Linus Walleij <linus.walleij@...aro.org>
Cc:     LKML <linux-kernel@...r.kernel.org>,
        kernel-janitors@...r.kernel.org, Daniel Vetter <daniel@...ll.ch>,
        David Airlie <airlied@...ux.ie>,
        Tang Bin <tangbin@...s.chinamobile.com>
Subject: drm/mcde: Checking for a failed platform_get_irq() call in
 mcde_probe()

Hello,

I have taken another look at the implementation of the function “mcde_probe”.
A software analysis approach points the following source code out for
further development considerations.
https://elixir.bootlin.com/linux/v5.6.2/source/drivers/gpu/drm/mcde/mcde_drv.c#L401
https://git.kernel.org/pub/scm/linux/kernel/git/torvalds/linux.git/tree/drivers/gpu/drm/mcde/mcde_drv.c?id=f5e94d10e4c468357019e5c28d48499f677b284f#n402

 	irq = platform_get_irq(pdev, 0);
 	if (!irq) {
 		ret = -EINVAL;
 		goto clk_disable;
 	}

The software documentation is providing the following information
for the used programming interface.
https://git.kernel.org/pub/scm/linux/kernel/git/torvalds/linux.git/tree/drivers/base/platform.c?id=f5e94d10e4c468357019e5c28d48499f677b284f#n221
https://elixir.bootlin.com/linux/v5.6.2/source/drivers/base/platform.c#L202

“…
 * Return: IRQ number on success, negative error number on failure.
…”

Would you like to reconsider the shown condition check?

Regards,
Markus