Date:   Fri, 15 May 2020 10:24:47 -0400
From:   Vineeth Remanan Pillai <vpillai@...italocean.com>
To:     Peter Zijlstra <peterz@...radead.org>
Cc:     Aaron Lu <aaron.lwe@...il.com>,
        Nishanth Aravamudan <naravamudan@...italocean.com>,
        Julien Desfossez <jdesfossez@...italocean.com>,
        Tim Chen <tim.c.chen@...ux.intel.com>,
        Ingo Molnar <mingo@...nel.org>,
        Thomas Gleixner <tglx@...utronix.de>,
        Paul Turner <pjt@...gle.com>,
        Linus Torvalds <torvalds@...ux-foundation.org>,
        Aaron Lu <aaron.lu@...ux.alibaba.com>,
        Linux List Kernel Mailing <linux-kernel@...r.kernel.org>,
        Frédéric Weisbecker <fweisbec@...il.com>,
        Kees Cook <keescook@...omium.org>,
        Greg Kerr <kerrnel@...gle.com>, Phil Auld <pauld@...hat.com>,
        Aubrey Li <aubrey.intel@...il.com>,
        "Li, Aubrey" <aubrey.li@...ux.intel.com>,
        Valentin Schneider <valentin.schneider@....com>,
        Mel Gorman <mgorman@...hsingularity.net>,
        Pawan Gupta <pawan.kumar.gupta@...ux.intel.com>,
        Paolo Bonzini <pbonzini@...hat.com>,
        Joel Fernandes <joelaf@...gle.com>,
        Joel Fernandes <joel@...lfernandes.org>
Subject: Re: [PATCH updated v2] sched/fair: core wide cfs task priority comparison

On Fri, May 15, 2020 at 6:39 AM Peter Zijlstra <peterz@...radead.org> wrote:
>
> It's complicated ;-)
>
> So this sync is basically a relative reset of S to 0.
>
> So with 2 queues, when one goes idle, we drop them both to 0 and one
> then increases due to not being idle, and the idle one builds up lag to
> get re-elected. So far so simple, right?
>
> When there's 3, we can have the situation where 2 run and one is idle,
> we sync to 0 and let the idle one build up lag to get re-election. Now
> suppose another one also drops idle. At this point dropping all to 0
> again would destroy the built-up lag from the queue that was already
> idle, not good.
>
Thanks for the clarification :-).

I was suggesting an idea of corewide force_idle. We sync the core_vruntime
on first force_idle of a sibling in the core and start using core_vruntime
for priority comparison from then on. That way, we don't reset the lag on
every force_idle and the lag builds up from the first sibling that was
forced_idle. I think this would work with infeasible weights as well,
but needs to think more to see if it would break. A sample check to enter
this core wide force_idle state is:
(cpumask_weight(cpu_smt_mask(cpu)) == old_active && new_active < old_active)

And we exit the core wide force_idle state when the last sibling goes out
of force_idle and can start using min_vruntime for priority comparison
from then on.

When there is a cookie match on all siblings, we don't do priority comparison
now. But I think we need to do priority comparison for cookie matches
also, so that we update 'max' in the loop. And for this comparison during
a no forced_idle scenario, I hope it should be fine to use the min_vruntime.
Updating 'max' in the loop when cookie matches is not really needed for SMT2,
but would be needed for SMTn.

This is just a wild idea on top of your patches. Might not be accurate
in all cases and need to think more about the corner cases. I thought I
would think it loud here :-)

> So instead of syncing everything, we can:
>
>   less := !((s64)(s_a - s_b) <= 0)
>
>   (v_a - S_a) - (v_b - S_b) == v_a - v_b - S_a + S_b
>                             == v_a - (v_b - S_a + S_b)
>
> IOW, we can recast the (lag) comparison to a one-sided difference.
> So if then, instead of syncing the whole queue, sync the idle queue
> against the active queue with S_a + S_b at the point where we sync.
>
> (XXX consider the implication of living in a cyclic group: N / 2^n N)
>
> This gives us means of syncing single queues against the active queue,
> and for already idle queues to preseve their build-up lag.
>
> Of course, then we get the situation where there's 2 active and one
> going idle, who do we pick to sync against? Theory would have us sync
> against the combined S, but as we've already demonstated, there is no
> such thing in infeasible weight scenarios.
>
> One thing I've considered; and this is where that core_active rudiment
> came from, is having active queues sync up between themselves after
> every tick. This limits the observed divergence due to the work
> conservance.
>
> On top of that, we can improve upon things by moving away from our
> horrible (10) hack and moving to (9) and employing (13) here.
>
> Anyway, I got partway through that in the past days, but then my head
> hurt. I'll consider it some more :-)
This sounds much better and a more accurate approach then the one I
mentioned above. Please share the code when you have it in some form :-)

>
> > > +                       new_active++;
> > I think we need to reset new_active on restarting the selection.
>
> But this loop is after selection has been done; we don't modify
> new_active during selection.
My bad, sorry about this false alarm!

> > > +
> > > +       vruntime_a = se_a->vruntime - cfs_rq_a->core_vruntime;
> > > +       vruntime_b = se_b->vruntime - cfs_rq_b->core_vruntime;
> > Should we be using core_vruntime conditionally? should it be min_vruntime for
> > default comparisons and core_vruntime during force_idle?
>
> At the very least it should be min_vruntime when cfs_rq_a == cfs_rq_b,
> ie. when we're on the same CPU.
>
yes, this makes sense.

The issue that I was thinking about is, when there is no force_idle and
all siblings run compatible tasks for a while, min_vruntime progresses,
but core_vruntime lags behind. And when a new task gets enqueued, it gets
the min_vruntime. But now during comparison it might be treated unfairly.

Consider a small example of two rqs rq1 and rq2.
rq1->cfs->min_vruntime = 1000
rq2->cfs->min_vruntime = 2000

During a force_idle, core_vruntime gets synced and

rq1->cfs->core_vruntime = 1000
rq2->cfs->core_vruntime = 2000

Now, suppose the core is out of force_idle and runs two compatible tasks
for a while, where the task on rq1 has more weight. min_vruntime progresses
on both, but slowly on rq1. Say the progress looks like:
rq1->cfs->min_vruntime = 1200, se1->vruntime = 1200
rq2->cfs->min_vruntime = 2500, se2->vruntime = 2500

If a new incompatible task(se3) gets enqueued to rq2, it's vruntime would
be based on rq2's min_vruntime, say:
se3->vruntime = 2500

During our priority comparison, lag would be:
l_se1 = 200
l_se3 = 500

So se1, will get selected and run with se2 until its lag catches up with
se3's lag(even if se3 has more weight than se1).

This is a hypothetical situation, but can happen I think. And if we use
min_vruntime for comparison during no force_idle scenario, we could
avoid this. What do you think?

I didn't clearly understand the tick based active sync and probably would
better fix this problem I guess.

Thanks,
Vineeth

Powered by blists - more mailing lists