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Date:   Thu, 1 Oct 2020 18:27:20 +0200
From:   Oleg Nesterov <oleg@...hat.com>
To:     Jens Axboe <axboe@...nel.dk>
Cc:     io-uring <io-uring@...r.kernel.org>,
        "linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
        Peter Zijlstra <peterz@...radead.org>,
        Thomas Gleixner <tglx@...utronix.de>
Subject: Re: [PATCH RFC v2] kernel: decouple TASK_WORK TWA_SIGNAL handling
 from signals

Jens,

I'll read this version tomorrow, but:

On 10/01, Jens Axboe wrote:
>
>  static inline int signal_pending(struct task_struct *p)
>  {
> -	return unlikely(test_tsk_thread_flag(p,TIF_SIGPENDING));
> +#ifdef TIF_TASKWORK
> +	/*
> +	 * TIF_TASKWORK isn't really a signal, but it requires the same
> +	 * behavior of restarting the system call to force a kernel/user
> +	 * transition.
> +	 */
> +	return unlikely(test_tsk_thread_flag(p, TIF_SIGPENDING) ||
> +			test_tsk_thread_flag(p, TIF_TASKWORK));
> +#else
> +	return unlikely(test_tsk_thread_flag(p, TIF_SIGPENDING));
> +#endif

This change alone is already very wrong.

signal_pending(task) == T means that this task will do get_signal() as
soon as it can, and this basically means you can't "divorce" SIGPENDING
and TASKWORK.

Simple example. Suppose we have a single-threaded task T.

Someone does task_work_add(T, TWA_SIGNAL). This makes signal_pending()==T
and this is what we need.

Now suppose that another task sends a signal to T before T calls
task_work_run() and clears TIF_TASKWORK. In this case SIGPENDING won't
be set because signal_pending() is already set (see wants_signal), and
this means that T won't notice this signal.

Oleg.

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