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Message-ID: <20201028201135.GA3913249@google.com>
Date: Wed, 28 Oct 2020 13:11:35 -0700
From: Prashant Malani <pmalani@...omium.org>
To: Heikki Krogerus <heikki.krogerus@...ux.intel.com>
Cc: linux-kernel@...r.kernel.org, Benson Leung <bleung@...omium.org>,
Enric Balletbo i Serra <enric.balletbo@...labora.com>,
Guenter Roeck <groeck@...omium.org>
Subject: Re: [PATCH 6/7] platform/chrome: cros_ec_typec: Parse partner PD ID
VDOs
Hi Heikki,
Thanks a lot for reviewing the patch!
On Wed, Oct 28, 2020 at 03:16:33PM +0200, Heikki Krogerus wrote:
> > +
> > + /* Copy the remaining identity VDOs till a maximum of 6. */
> > + for (i = 3; i < sop_disc->identity_count && i < VDO_MAX_OBJECTS; i++)
> > + port->p_identity.vdo[i - 3] = sop_disc->discovery_vdo[i];
>
> Why do you need to put the product type VDOs in reverse order?
The Chrome EC returns all the Identity VDOs as an array of 6 VDOs (the
discovery_vdo[] array). The first three entries are assigned to the
pd_identity.{id_header,cert_stat,product} members.
This for loop assigns the next three discovery_vdo entries (i.e indices
3-5) to pd_identity.vdo[0-2] respectively.
The "i-3" is because discovery_vdo[3] corresponds to pd_identity.vdo[0]
and so on.
Does that help to clarify the for loop?
Best regards,
Prashant
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