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Message-ID: <87sg8ch0k4.fsf@nanos.tec.linutronix.de>
Date: Fri, 11 Dec 2020 15:36:27 +0100
From: Thomas Gleixner <tglx@...utronix.de>
To: Sebastian Andrzej Siewior <bigeasy@...utronix.de>,
"Paul E. McKenney" <paulmck@...nel.org>
Cc: LKML <linux-kernel@...r.kernel.org>,
Marco Elver <elver@...gle.com>,
kasan-dev <kasan-dev@...glegroups.com>,
Peter Zijlstra <peterz@...radead.org>,
Anna-Maria Behnsen <anna-maria@...utronix.de>
Subject: Re: timers: Move clearing of base::timer_running under base::lock
On Tue, Dec 08 2020 at 09:50, Sebastian Andrzej Siewior wrote:
> On 2020-12-07 08:06:48 [-0800], Paul E. McKenney wrote:
>> > Yes, but it triggers frequently. Like `rcuc' is somehow is aligned with
>> > the timeout.
>>
>> Given that a lot of RCU processing is event-driven based on timers,
>> and given that the scheduling-clock interrupts are synchronized for
>> energy-efficiency reasons on many configs, maybe this alignment is
>> expected behavior?
>
> No, it is the fact that rcu_preempt has a higher priority than
> ksoftirqd. So immediately after the wakeup (of rcu_preempt) there is a
> context switch and expire_timers() has this:
>
> | raw_spin_unlock_irq(&base->lock);
> | call_timer_fn(timer, fn, baseclk);
> | raw_spin_lock_irq(&base->lock);
> | base->running_timer = NULL;
> | timer_sync_wait_running(base);
>
> So ->running_timer isn't reset and try_to_del_timer_sync() (that
> del_timer_sync() from schedule_timeout()) returns -1 and then the corner
> case is handled where `expiry_lock' is acquired. So everything goes as
> expected.
Well, but even without that change you have the same situation:
timer_fn()
wakeup()
-->preemption
del_timer_sync()
if (running)
wait_for_running()
lock(expiry)
running = NULL
sync_wait_running()
unlock(expiry)
wakeup_lock()
-->preemption
...
lock(base)
So the change at hand does not make things worse, right?
Thanks,
tglx
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