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Message-Id: <68D3C593-A88C-4100-90E9-E90F7733344F@gmail.com>
Date: Sat, 30 Jan 2021 17:17:31 -0800
From: Nadav Amit <nadav.amit@...il.com>
To: Andy Lutomirski <luto@...nel.org>
Cc: Andrew Cooper <andrew.cooper3@...rix.com>,
Linux-MM <linux-mm@...ck.org>,
LKML <linux-kernel@...r.kernel.org>,
Andrea Arcangeli <aarcange@...hat.com>,
Andrew Morton <akpm@...ux-foundation.org>,
Dave Hansen <dave.hansen@...ux.intel.com>,
Peter Zijlstra <peterz@...radead.org>,
Thomas Gleixner <tglx@...utronix.de>,
Will Deacon <will@...nel.org>, Yu Zhao <yuzhao@...gle.com>,
Nick Piggin <npiggin@...il.com>, X86 ML <x86@...nel.org>
Subject: Re: [RFC 03/20] mm/mprotect: do not flush on permission promotion
> On Jan 30, 2021, at 5:07 PM, Andy Lutomirski <luto@...nel.org> wrote:
>
> Adding Andrew Cooper, who has a distressingly extensive understanding
> of the x86 PTE magic.
>
> On Sat, Jan 30, 2021 at 4:16 PM Nadav Amit <nadav.amit@...il.com> wrote:
>> From: Nadav Amit <namit@...are.com>
>>
>> Currently, using mprotect() to unprotect a memory region or uffd to
>> unprotect a memory region causes a TLB flush. At least on x86, as
>> protection is promoted, no TLB flush is needed.
>>
>> Add an arch-specific pte_may_need_flush() which tells whether a TLB
>> flush is needed based on the old PTE and the new one. Implement an x86
>> pte_may_need_flush().
>>
>> For x86, besides the simple logic that PTE protection promotion or
>> changes of software bits does require a flush, also add logic that
>> considers the dirty-bit. If the dirty-bit is clear and write-protect is
>> set, no TLB flush is needed, as x86 updates the dirty-bit atomically
>> on write, and if the bit is clear, the PTE is reread.
>>
>> Signed-off-by: Nadav Amit <namit@...are.com>
>> Cc: Andrea Arcangeli <aarcange@...hat.com>
>> Cc: Andrew Morton <akpm@...ux-foundation.org>
>> Cc: Andy Lutomirski <luto@...nel.org>
>> Cc: Dave Hansen <dave.hansen@...ux.intel.com>
>> Cc: Peter Zijlstra <peterz@...radead.org>
>> Cc: Thomas Gleixner <tglx@...utronix.de>
>> Cc: Will Deacon <will@...nel.org>
>> Cc: Yu Zhao <yuzhao@...gle.com>
>> Cc: Nick Piggin <npiggin@...il.com>
>> Cc: x86@...nel.org
>> ---
>> arch/x86/include/asm/tlbflush.h | 44 +++++++++++++++++++++++++++++++++
>> include/asm-generic/tlb.h | 4 +++
>> mm/mprotect.c | 3 ++-
>> 3 files changed, 50 insertions(+), 1 deletion(-)
>>
>> diff --git a/arch/x86/include/asm/tlbflush.h b/arch/x86/include/asm/tlbflush.h
>> index 8c87a2e0b660..a617dc0a9b06 100644
>> --- a/arch/x86/include/asm/tlbflush.h
>> +++ b/arch/x86/include/asm/tlbflush.h
>> @@ -255,6 +255,50 @@ static inline void arch_tlbbatch_add_mm(struct arch_tlbflush_unmap_batch *batch,
>>
>> extern void arch_tlbbatch_flush(struct arch_tlbflush_unmap_batch *batch);
>>
>> +static inline bool pte_may_need_flush(pte_t oldpte, pte_t newpte)
>> +{
>> + const pteval_t ignore_mask = _PAGE_SOFTW1 | _PAGE_SOFTW2 |
>> + _PAGE_SOFTW3 | _PAGE_ACCESSED;
>
> Why is accessed ignored? Surely clearing the accessed bit needs a
> flush if the old PTE is present.
I am just following the current scheme in the kernel (x86):
int ptep_clear_flush_young(struct vm_area_struct *vma,
unsigned long address, pte_t *ptep)
{
/*
* On x86 CPUs, clearing the accessed bit without a TLB flush
* doesn't cause data corruption. [ It could cause incorrect
* page aging and the (mistaken) reclaim of hot pages, but the
* chance of that should be relatively low. ]
*
* So as a performance optimization don't flush the TLB when
* clearing the accessed bit, it will eventually be flushed by
* a context switch or a VM operation anyway. [ In the rare
* event of it not getting flushed for a long time the delay
* shouldn't really matter because there's no real memory
* pressure for swapout to react to. ]
*/
return ptep_test_and_clear_young(vma, address, ptep);
}
>
>> + const pteval_t enable_mask = _PAGE_RW | _PAGE_DIRTY | _PAGE_GLOBAL;
>> + pteval_t oldval = pte_val(oldpte);
>> + pteval_t newval = pte_val(newpte);
>> + pteval_t diff = oldval ^ newval;
>> + pteval_t disable_mask = 0;
>> +
>> + if (IS_ENABLED(CONFIG_X86_64) || IS_ENABLED(CONFIG_X86_PAE))
>> + disable_mask = _PAGE_NX;
>> +
>> + /* new is non-present: need only if old is present */
>> + if (pte_none(newpte))
>> + return !pte_none(oldpte);
>> +
>> + /*
>> + * If, excluding the ignored bits, only RW and dirty are cleared and the
>> + * old PTE does not have the dirty-bit set, we can avoid a flush. This
>> + * is possible since x86 architecture set the dirty bit atomically while
>
> s/set/sets/
>
>> + * it caches the PTE in the TLB.
>> + *
>> + * The condition considers any change to RW and dirty as not requiring
>> + * flush if the old PTE is not dirty or not writable for simplification
>> + * of the code and to consider (unlikely) cases of changing dirty-bit of
>> + * write-protected PTE.
>> + */
>> + if (!(diff & ~(_PAGE_RW | _PAGE_DIRTY | ignore_mask)) &&
>> + (!(pte_dirty(oldpte) || !pte_write(oldpte))))
>> + return false;
>
> This logic seems confusing to me. Is your goal to say that, if the
> old PTE was clean and writable and the new PTE is write-protected,
> then no flush is needed?
Yes.
> If so, I would believe you're right, but I'm
> not convinced you've actually implemented this. Also, there may be
> other things going on that need flushing, e.g. a change of the address
> or an accessed bit or NX change.
The first part (diff & ~(_PAGE_RW | _PAGE_DIRTY | ignore_mask) is supposed
to capture changes of address, NX-bit, etc.
The second part is indeed wrong. It should have been:
(!pte_dirty(oldpte) || !pte_write(oldpte))
>
> Also, CET makes this extra bizarre.
I saw something about the not-writeable-and-dirty considered differently. I
need to have a look, but I am not sure it affects anything.
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