linux-kernel - Re: [PATCH 00/13] [RFC] Rust support

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Date:   Sat, 17 Apr 2021 14:01:48 +0100
From:   Wedson Almeida Filho <wedsonaf@...gle.com>
To:     David Laight <David.Laight@...lab.com>
Cc:     'Peter Zijlstra' <peterz@...radead.org>,
        "ojeda@...nel.org" <ojeda@...nel.org>,
        Linus Torvalds <torvalds@...ux-foundation.org>,
        Greg Kroah-Hartman <gregkh@...uxfoundation.org>,
        "rust-for-linux@...r.kernel.org" <rust-for-linux@...r.kernel.org>,
        "linux-kbuild@...r.kernel.org" <linux-kbuild@...r.kernel.org>,
        "linux-doc@...r.kernel.org" <linux-doc@...r.kernel.org>,
        "linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH 00/13] [RFC] Rust support

On Sat, Apr 17, 2021 at 12:41:23PM +0000, David Laight wrote:
> Or the cases where the locks are released in the 'wrong' order.
> Typically for:
> 	lock(table)
> 	item = lookup(table, key)
> 	lock(item)
> 	unlock(table)
> 	...
> 	unlock(item)

This is expressible in Rust with something like:

    table = table_mutex.lock()
    item = table.lookup(key).lock()
    drop(table)
    ...
    // item will be unlocked when it goes out of scope or on drop(item)

The added bonus here from Rust is that table is not accessible after
drop(table), so a developer cannot accidentally access fields after unlocking
it.

> 
> (In the kernel the table lock might be RCU.)
> 
> Or, with similar data:
> 	write_lock(table);
> 	foreach(item, table)
> 		lock(item)
> 		unlock(item)
> 	/* No items can be locked until we release the write_lock.
> 	...
> 	unlock(table)

I think I'm missing something here. Would you help me understand what part is
out of the ordinary in the code above? It would be expressible in Rust with
something like:

    table = table_mutex.write();
    for (item_mutex in table)
        item = item_mutex.lock
        // item is unlocked at the end of the loop iteration (out of scope)
    // table gets unlocked when it goes out of scope

Cheers,
-Wedson