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Date:   Thu, 10 Jun 2021 16:44:47 +0200
From:   John Ogness <john.ogness@...utronix.de>
To:     Petr Mladek <pmladek@...e.com>
Cc:     Sergey Senozhatsky <senozhatsky@...omium.org>,
        Steven Rostedt <rostedt@...dmis.org>,
        Thomas Gleixner <tglx@...utronix.de>,
        linux-kernel@...r.kernel.org,
        Peter Zijlstra <peterz@...radead.org>,
        "Paul E. McKenney" <paulmck@...nel.org>
Subject: Re: [PATCH next v2 2/2] printk: fix cpu lock ordering

On 2021-06-08, Petr Mladek <pmladek@...e.com> wrote:
>> 	/*
>> 	 * Guarantee loads and stores from this CPU when it is the lock owner
>> 	 * are _not_ visible to the previous lock owner. This pairs with
>> 	 * cpu_unlock:B.
>> 	 *
>> 	 * Memory barrier involvement:
>> 	 *
>> 	 * If cpu_lock:A reads from cpu_unlock:B, then cpu_unlock:A can never
>> 	 * read from cpu_lock:B.
>> 	 *
>> 	 * Relies on:
>> 	 *
>> 	 * RELEASE from cpu_unlock:A to cpu_unlock:B
>> 	 *    matching
>> 	 * ACQUIRE from cpu_lock:A to cpu_lock:B
>> 	 */
>
> I can't check this so I believe you ;-)

I appreciate your confidence in me, but for the record, we should
operate on proofs. Here is a litmus test for this case that is only
using the 2 memory barriers described in the coments. I also added
commented out non-memory-barrier variants so you can quickly check what
happens if either memory barrier is removed.

-------- BEGIN prevent_backwards_leak.litmus --------
C prevent_backwards_leak

(*
 * Guarantee a previous CPU (P0) in the critical section cannot
 * see data stored by the next CPU (P1) in the critical section.
 *
 * RELEASE in P0 matches ACQUIRE in P1
 *)

{ }

P0(int *lck, int *var)
{
	int old;
	int val;

	old = atomic_cmpxchg_relaxed(lck, 0, 1);
	if (old == 0) {
		val = *var;
		atomic_set_release(lck, 2);
		//atomic_set(lck, 2);
	}
}

P1(int *lck, int *var)
{
	int old;

	old = atomic_cmpxchg_acquire(lck, 2, 3);
	//old = atomic_cmpxchg_relaxed(lck, 2, 3);
	if (old == 2) {
		*var = 1;
		atomic_set(lck, 3);
	}
}

exists (1:old=2 /\ 0:val=1)
-------- END prevent_backwards_leak.litmus --------

And running it shows:

$ herd7 -conf linux-kernel.cfg prevent_backwards_leak.litmus
Test prevent_backwards_leak Allowed
States 3
0:val=0; 1:old=0;
0:val=0; 1:old=1;
0:val=0; 1:old=2;
No
Witnesses
Positive: 0 Negative: 3
Condition exists (1:old=2 /\ 0:val=1)
Observation prevent_backwards_leak Never 0 3
Time prevent_backwards_leak 0.01
Hash=a83f3a63382111d7f61810639fa38ad4

If either of the two memory barriers are removed, the results will show
that @val in first CPU (P0) can be 1 (0:val=1), which was the value set
by the following CPU (P1) in the critical section.

>> 	/*
>> 	 * Guarantee loads and stores from this CPU when it was the
>> 	 * lock owner are visible to the next lock owner. This pairs
>> 	 * with cpu_lock:A.
>> 	 *
>> 	 * Memory barrier involvement:
>> 	 *
>> 	 * If cpu_lock:A reads from cpu_unlock:B, then cpu_lock:B
>> 	 * reads from cpu_unlock:A.
>> 	 *
>> 	 * Relies on:
>> 	 *
>> 	 * RELEASE from cpu_unlock:A to cpu_unlock:B
>> 	 *    matching
>> 	 * ACQUIRE from cpu_lock:A to cpu_lock:B
>> 	 */
>
> Same as for acquire ;-)

And here is the litmus test for this case, also with extra commented out
non-memory-barrier variants.

-------- BEGIN guarantee_forward_visibility.litmus --------
C guarantee_forward_visibility

(*
 * Guarantee data stored by a previous CPU (P0) in the critical
 * section is always visible to the next CPU (P1) in the critical
 * section.
 *
 * RELEASE in P0 matches ACQUIRE in P1
 *)

{ }

P0(int *lck, int *var)
{
	int old;

	old = atomic_cmpxchg_relaxed(lck, 0, 1);
	if (old == 0) {
		*var = 1;
		atomic_set_release(lck, 2);
		//atomic_set(lck, 2);
	}
}

P1(int *lck, int *var)
{
	int old;
	int val;

	old = atomic_cmpxchg_acquire(lck, 2, 3);
	//old = atomic_cmpxchg_relaxed(lck, 2, 3);
	if (old == 2) {
		val = *var;
		atomic_set(lck, 3);
	}
}

exists (1:old=2 /\ 1:val=0 )
-------- END guarantee_forward_visibility.litmus --------

$ herd7 -conf linux-kernel.cfg guarantee_forward_visibility.litmus
Test guarantee_forward_visibility Allowed
States 3
1:old=0; 1:val=0;
1:old=1; 1:val=0;
1:old=2; 1:val=1;
No
Witnesses
Positive: 0 Negative: 3
Condition exists (1:old=2 /\ 1:val=0)
Observation guarantee_forward_visibility Never 0 3
Time guarantee_forward_visibility 0.00
Hash=fad189f07da06da99b97a7ab1215a5dc

Also here, if either of the memory barriers are removed, @val in the
later CPU (P1) can be 0 (1:val=0). Meaning that the a following CPU in
the critical section would not see a value set by the previous CPU in
the critical section.

John Ogness

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