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Message-ID: <YO6qfQMcvr9szZTJ@smile.fi.intel.com>
Date: Wed, 14 Jul 2021 12:12:29 +0300
From: Andy Shevchenko <andriy.shevchenko@...ux.intel.com>
To: Liu Ying <victor.liu@....com>
Cc: linux-clk@...r.kernel.org, linux-kernel@...r.kernel.org,
Heikki Krogerus <heikki.krogerus@...ux.intel.com>,
Michael Turquette <mturquette@...libre.com>,
Stephen Boyd <sboyd@...nel.org>,
Dong Aisheng <aisheng.dong@....com>,
NXP Linux Team <linux-imx@....com>,
Jacky Bai <ping.bai@....com>
Subject: Re: [RFC PATCH] clk: fractional-divider: Correct max_{m,n} handed
over to rational_best_approximation()
On Wed, Jul 14, 2021 at 02:41:29PM +0800, Liu Ying wrote:
> If a fractional divider clock has the flag
> CLK_FRAC_DIVIDER_ZERO_BASED set, the maximum
> numerator and denominator handed over to
> rational_best_approximation(), in this case
> max_m and max_n, should be increased by one
> comparing to those have the flag unset. Without
> this patch, a zero based fractional divider
> with 1-bit mwidth and 3-bit nwidth would wrongly
> generate 96MHz clock rate if the parent clock
> rate is 288MHz, while the expected clock rate
> is 115.2MHz with m = 2 and n = 5.
Make sure that your editor is configured to allow you to have lines ~70-72
characters long.
...
> The patch is RFC, because the rationale behind the below snippet in
> clk_fd_general_approximation() is unclear to Jacky and me and we are
> not sure if there is any room to improve this patch due to the snippet.
> Maybe, Andy may help shed some light here. Thanks.
>
> -----------------------------------8<---------------------------------
> /*
> * Get rate closer to *parent_rate to guarantee there is no overflow
> * for m and n. In the result it will be the nearest rate left shifted
> * by (scale - fd->nwidth) bits.
> */
I don't know how to rephrase above comment better.
> scale = fls_long(*parent_rate / rate - 1);
> if (scale > fd->nwidth)
> rate <<= scale - fd->nwidth;
This takes an advantage of the numbers be in a form of
n = k * 2^m, (1)
where m will be scale in the snippet above. Thus, if n can be represented by
(1), we opportunistically reduce amount of bits needed for it by shifting right
by m bits.
Does it make sense?
The code looks good to me, btw, although I dunno if you need to call the newly
introduced function before or after the above mentioned snippet.
--
With Best Regards,
Andy Shevchenko
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