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Message-ID: <bfa0c16e88c0d445137290b2bef104e5fa74d78a.camel@nxp.com>
Date: Mon, 19 Jul 2021 11:16:07 +0800
From: Liu Ying <victor.liu@....com>
To: Andy Shevchenko <andriy.shevchenko@...ux.intel.com>
Cc: Heiko Stuebner <heiko@...ech.de>,
Elaine Zhang <zhangqing@...k-chips.com>,
Stephen Boyd <sboyd@...nel.org>, linux-kernel@...r.kernel.org,
linux-clk@...r.kernel.org, linux-arm-kernel@...ts.infradead.org,
linux-rockchip@...ts.infradead.org,
Michael Turquette <mturquette@...libre.com>,
NXP Linux Team <linux-imx@....com>,
Jacky Bai <ping.bai@....com>
Subject: Re: [PATCH v1 2/3] clk: fractional-divider: Introduce NO_PRESCALER
flag
On Fri, 2021-07-16 at 16:19 +0300, Andy Shevchenko wrote:
> On Fri, Jul 16, 2021 at 10:43:57AM +0800, Liu Ying wrote:
> > On Thu, 2021-07-15 at 15:07 +0300, Andy Shevchenko wrote:
> > > The newly introduced flag, when set, makes the flow to skip
> > > the assumption that the caller will use an additional 2^scale
> > > prescaler to get the desired clock rate.
> >
> > Now, I start to be aware of the reason why the "left shifting" is
> > needed but still not 100% sure that details are all right. IIUC, you
> > are considering a potential HW prescaler here, while I thought the HW
> > model is just a fractional divider(M/N) and the driver is fully
> > agnostic to the potential HW prescaler.
>
> It's not AFAICS. Otherwise we will get saturated values which is much worse
> then shifted left frequency. Anyway, this driver appeared first for the hardware
> that has it for all users, so currently the assumption stays.
>
> ...
>
> > > scale = fls_long(*parent_rate / rate - 1);
> > > - if (scale > fd->nwidth)
> > > + if (scale > fd->nwidth && !(fd->flags & CLK_FRAC_DIVIDER_NO_PRESCALER))
> > > rate <<= scale - fd->nwidth;
> >
> > First of all, check the CLK_FRAC_DIVIDER_NO_PRESCALER flag for the
> > entire above snippet of code?
>
> OK.
>
> > Second and more important, it seems that it would be good to decouple
> > the prescaler knowledge from this fractional divider clk driver so as
> > to make it simple(Output rate = (m / n) * parent_rate). This way, the
> > CLK_FRAC_DIVIDER_NO_PRESCALER flag is not even needed at the first
> > place, which means rational_best_approximation() just _directly_
> > offer best_{numerator,denominator} for all cases.
>
> Feel free to submit a patch, just give a good test to avoid breakage of almost
> all users of this driver.
Maybe someone may do that. I just shared my thought that it sounds
like a good idea to decouple the prescaler knowledge from this
fractional divider clk driver.
>
> > Further more, is it
> > possilbe for rational_best_approximation() to make sure there is no
> > risk of overflow for best_{numerator,denominator}, since
> > max_{numerator,denominator} are already handed over to
> > rational_best_approximation()?
>
> How? It can not be satisfied for all possible inputs.
Just have rational_best_approximation() make sure
best_{numerator,denominator} are in the range of
[1, max_{numerator,denominator}] for all given_{numerator,denominator}.
At the same time, best_numerator/best_denominator should be as close
to given_numerator/given_denominator as possible. For this particular
fractional divider clk use case, clk_round_rate() can be called
multiple times until users find rounded rate is ok.
>
> > Overflowed/unreasonable
> > best_{numerator,denominator} don't sound like the "best" offered value.
>
> I don't follow here. If you got saturated values it means that your input is
> not convergent. In practice it means that we will supply quite a bad value to
> the caller.
Just like I mentioned above, if given_{numerator,denominator} are not
convergent, best_numerator/best_denominator should be as close
to given_numerator/given_denominator as possible and at the same time
best_{numerator,denominator} are in the range of
[1, max_{numerator,denominator}]. This way, caller may have chance to
propose convergent inputs.
Regards,
Liu Ying
>
> > If that's impossible, then audit best_{numerator,denominator} after
> > calling rational_best_approximation()?
>
> And? I do not understand what you will do if you get the values of m and n
> as m = 1, n = 2^nlim - 1.
>
> > Make sense?
>
> Not really. I probably miss your point, sorry.
>
> So, I will submit v2 with addressed first comment and LKP noticed compiler
> error.
>
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