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Message-ID: <87b411c3-da75-e074-91a4-a73891f9f5f8@redhat.com>
Date: Wed, 22 Sep 2021 12:02:42 +0200
From: Paolo Bonzini <pbonzini@...hat.com>
To: Hao Xiang <hao.xiang@...ux.alibaba.com>, kvm@...r.kernel.org
Cc: linux-kernel@...r.kernel.org, chenyi.qiang@...el.com,
sean.j.christopherson@...el.com, shannon.zhao@...ux.alibaba.com
Subject: Re: [PATCH] KVM: VMX: Check if bus lock vmexit was preempted
On 18/09/21 13:30, Hao Xiang wrote:
> exit_reason.bus_lock_detected is not only set when bus lock VM exit
> was preempted, in fact, this bit is always set if bus locks are
> detected no matter what the exit_reason.basic is.
>
> So the bus_lock_vmexit handling in vmx_handle_exit should be duplicated
> when exit_reason.basic is EXIT_REASON_BUS_LOCK(74). We can avoid it by
> checking if bus lock vmexit was preempted in vmx_handle_exit.
I don't understand, does this mean that bus_lock_detected=1 if
basic=EXIT_REASON_BUS_LOCK? If so, can we instead replace the contents
of handle_bus_lock_vmexit with
/* Do nothing and let vmx_handle_exit exit to userspace. */
WARN_ON(!to_vmx(vcpu)->exit_reason.bus_lock_detected);
return 0;
?
That would be doable only if this is architectural behavior and not a
processor erratum, of course.
Thanks,
Paolo
> Signed-off-by: Hao Xiang <hao.xiang@...ux.alibaba.com>
> ---
> arch/x86/kvm/vmx/vmx.c | 3 ++-
> 1 file changed, 2 insertions(+), 1 deletion(-)
>
> diff --git a/arch/x86/kvm/vmx/vmx.c b/arch/x86/kvm/vmx/vmx.c
> index 0c2c0d5..5ddf1df 100644
> --- a/arch/x86/kvm/vmx/vmx.c
> +++ b/arch/x86/kvm/vmx/vmx.c
> @@ -6054,7 +6054,8 @@ static int vmx_handle_exit(struct kvm_vcpu *vcpu, fastpath_t exit_fastpath)
> * still need to exit to user space when bus lock detected to inform
> * that there is a bus lock in guest.
> */
> - if (to_vmx(vcpu)->exit_reason.bus_lock_detected) {
> + if (to_vmx(vcpu)->exit_reason.bus_lock_detected &&
> + to_vmx(vcpu)->exit_reason.basic != EXIT_REASON_BUS_LOCK) {
> if (ret > 0)
> vcpu->run->exit_reason = KVM_EXIT_X86_BUS_LOCK;
>
>
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