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Date:   Mon, 15 Nov 2021 17:29:10 -0500
From:   Waiman Long <longman@...hat.com>
To:     Peter Zijlstra <peterz@...radead.org>
Cc:     Ingo Molnar <mingo@...hat.com>, Will Deacon <will@...nel.org>,
        linux-kernel@...r.kernel.org, Davidlohr Bueso <dave@...olabs.net>,
        mazhenhua <mazhenhua@...omi.com>,
        Hillf Danton <hdanton@...a.com>,
        Maria Yu <quic_aiquny@...cinc.com>
Subject: Re: [PATCH v4] locking/rwsem: Make handoff bit handling more
 consistent


On 11/15/21 11:01, Peter Zijlstra wrote:
> On Sun, Nov 14, 2021 at 10:38:57PM -0500, Waiman Long wrote:
>> On 11/12/21 07:10, Peter Zijlstra wrote:
>>> Argh, rwsem_mark_wake() doesn't clear HANDOFF when list_empty(), and
>>> write_slowpath() is *far* too clever about all of this.
>> rwsem_mark_wake() does clear the HANDOFF flag if it was set.
> Argh, yeah, I got confused by the whole !woken case, but that case won't
> ever hit list_empty() either. Perhaps that stuff could use a bit of a
> reflow too.
I think your modification already have included the rewrite for that part.
>
>>>> @@ -1098,7 +1110,7 @@ rwsem_down_write_slowpath(struct rw_semaphore *sem, int state)
>>>>    		 * In this case, we attempt to acquire the lock again
>>>>    		 * without sleeping.
>>>>    		 */
>>>> -		if (wstate == WRITER_HANDOFF) {
>>>> +		if (waiter.handoff_set) {
>>> I'm thinking this wants to be something like:
>>>
>>> 		if (rwsem_first_waiter(sem) == &waiter && waiter.handoff_set) {
>> handoff_set flag is only set when the waiter becomes the first.
> Yes, but a random waiter can wake up and see it be set and also start
> spinning.

The handoff_set flag can only be true for a first waiter. A random 
waiter in the middle of a wait queue will never has this flag set.

This flag is set in two places in rwsem_try_write_lock():

1)

                if (has_handoff && !first)
                         return false;
                 new = count;

                 if (count & RWSEM_LOCK_MASK) {
                         /*
                          * Only the first waiter can inherit a 
previously set
                          * handoff bit.
                          */
                         waiter->handoff_set = has_handoff;

handoff_set can only be set to true here if first is also true. In that 
case, it will also return false immediately afterward.

2)

         if (new & RWSEM_FLAG_HANDOFF) {
                 waiter->handoff_set = true;
                 lockevent_inc(rwsem_wlock_handoff);
                 return false;
         }

Again, only first waiter will have a chance of setting the handoff bit 
and have handoff_set set to true.

>>>>    			enum owner_state owner_state;
>>>>    			preempt_disable();
>>> @@ -575,6 +610,11 @@ static inline bool rwsem_try_write_lock(
>>>    		return false;
>>>    	}
>>> +	/*
>>> +	 * Have rwsem_try_write_lock() fully imply rwsem_del_waiter() on
>>> +	 * success.
>>> +	 */
>>> +	list_del(&waiter->list);
>>>    	rwsem_set_owner(sem);
>>>    	return true;
>>>    }
>>> @@ -1128,16 +1153,14 @@ rwsem_down_write_slowpath(struct rw_sema
>>>    		raw_spin_lock_irq(&sem->wait_lock);
>>>    	}
>>>    	__set_current_state(TASK_RUNNING);
>>> -	list_del(&waiter.list);
>> +    rwsem_del_waiter(sem, &waiters); ?
> I tried that, but then we get an extra atomic in this path. As is I made
> try_write_lock() do the full del_waiter, see the hunk above.

You are right. I missed your change in rwsem_try_write_lock().

Thanks,
Longman


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