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Message-ID: <95d91f5f-c5e1-0750-ebb9-b6839aecdc7c@linux-m68k.org>
Date: Mon, 17 Jan 2022 14:03:45 +1000
From: Greg Ungerer <gerg@...ux-m68k.org>
To: Hangyu Hua <hbh25y@...il.com>, geert@...ux-m68k.org
Cc: schwab@...ux-m68k.org, linux-m68k@...ts.linux-m68k.org,
linux-kernel@...r.kernel.org
Subject: Re: [PATCH v2 RESEND] m68k/kernel: array out of bound access in
process_uboot_commandline
Hi Hangyu,
On 13/1/22 11:58 am, Hangyu Hua wrote:
> When the size of commandp >= size, array out of bound write occurs because
> len == 0.
>
> Signed-off-by: Hangyu Hua <hbh25y@...il.com>
> ---
> arch/m68k/kernel/uboot.c | 3 ++-
> 1 file changed, 2 insertions(+), 1 deletion(-)
>
> diff --git a/arch/m68k/kernel/uboot.c b/arch/m68k/kernel/uboot.c
> index 928dbd33fc4a..63eaf3c3ddcd 100644
> --- a/arch/m68k/kernel/uboot.c
> +++ b/arch/m68k/kernel/uboot.c
> @@ -101,5 +101,6 @@ __init void process_uboot_commandline(char *commandp, int size)
> }
>
> parse_uboot_commandline(commandp, len);
> - commandp[len - 1] = 0;
> + if (len > 0)
> + commandp[len - 1] = 0;
> }
>
I am not convinced this is wrong for the reason you think it is.
Looking at the code in its entirety:
__init void process_uboot_commandline(char *commandp, int size)
{
int len, n;
n = strnlen(commandp, size);
commandp += n;
len = size - n;
if (len) {
/* Add the whitespace separator */
*commandp++ = ' ';
len--;
}
parse_uboot_commandline(commandp, len);
commandp[len - 1] = 0;
}
"commandp" is moved based on the return of the strnlen(). So in the
case of commandp actually being full of valid characters (so n == size,
and thus len == 0) the commandp technically points outside of its
real size at that point. But "command[[len - 1]" would actually be
pointing to the last char in the original commandp array (so the original
commandp[size - 1]). Well at least if you are happy with the use of
negative array indexes.
Clearly this could be structured better. There is no point in calling
parse_uboot_commandline() if len == 0, or even if len == 1, since you
cannot add anymore to the command line, it is full.
Regards
Greg
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