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Date:   Thu, 3 Feb 2022 11:49:12 -0700
From:   Jens Axboe <axboe@...nel.dk>
To:     Usama Arif <usama.arif@...edance.com>, io-uring@...r.kernel.org,
        asml.silence@...il.com, linux-kernel@...r.kernel.org
Cc:     fam.zheng@...edance.com
Subject: Re: [PATCH v4 2/3] io_uring: avoid ring quiesce while
 registering/unregistering eventfd

On 2/3/22 11:24 AM, Usama Arif wrote:
> -static inline bool io_should_trigger_evfd(struct io_ring_ctx *ctx)
> +static void io_eventfd_signal(struct io_ring_ctx *ctx)
>  {
> -	if (likely(!ctx->cq_ev_fd))
> -		return false;
> +	struct io_ev_fd *ev_fd;
> +
> +	rcu_read_lock();
> +	/* rcu_dereference ctx->io_ev_fd once and use it for both for checking and eventfd_signal */
> +	ev_fd = rcu_dereference(ctx->io_ev_fd);
> +
> +	if (likely(!ev_fd))
> +		goto out;
>  	if (READ_ONCE(ctx->rings->cq_flags) & IORING_CQ_EVENTFD_DISABLED)
> -		return false;
> -	return !ctx->eventfd_async || io_wq_current_is_worker();
> +		goto out;
> +
> +	if (!ctx->eventfd_async || io_wq_current_is_worker())
> +		eventfd_signal(ev_fd->cq_ev_fd, 1);
> +
> +out:
> +	rcu_read_unlock();
>  }

This still needs what we discussed in v3, something ala:

/*
 * This will potential race with eventfd registration, but that's
 * always going to be the case if there is IO inflight while an eventfd
 * descriptor is being registered.
 */
if (!rcu_dereference_raw(ctx->io_ev_fd))
	return;

rcu_read_lock();
...

which I think is cheap enough and won't hit sparse complaints. The

> @@ -9353,35 +9370,70 @@ static int __io_sqe_buffers_update(struct io_ring_ctx *ctx,
>  
>  static int io_eventfd_register(struct io_ring_ctx *ctx, void __user *arg)
>  {
> +	struct io_ev_fd *ev_fd;
>  	__s32 __user *fds = arg;
> -	int fd;
> +	int fd, ret;
>  
> -	if (ctx->cq_ev_fd)
> -		return -EBUSY;
> +	mutex_lock(&ctx->ev_fd_lock);
> +	ret = -EBUSY;
> +	if (rcu_dereference_protected(ctx->io_ev_fd, lockdep_is_held(&ctx->ev_fd_lock))) {
> +		rcu_barrier();
> +		if(rcu_dereference_protected(ctx->io_ev_fd, lockdep_is_held(&ctx->ev_fd_lock)))
> +			goto out;
> +	}

I wonder if we can get away with assigning ctx->io_ev_fd to NULL when we
do the call_rcu(). The struct itself will remain valid as long as we're
under rcu_read_lock() protection, so I think we'd be fine? If we do
that, then we don't need any rcu_barrier() or synchronize_rcu() calls,
as we can register a new one while the previous one is still being
killed.

Hmm?

>  static int io_eventfd_unregister(struct io_ring_ctx *ctx)
>  {
> -	if (ctx->cq_ev_fd) {
> -		eventfd_ctx_put(ctx->cq_ev_fd);
> -		ctx->cq_ev_fd = NULL;
> -		return 0;
> +	struct io_ev_fd *ev_fd;
> +	int ret;
> +
> +	mutex_lock(&ctx->ev_fd_lock);
> +	ev_fd = rcu_dereference_protected(ctx->io_ev_fd, lockdep_is_held(&ctx->ev_fd_lock));
> +	if (ev_fd) {
> +		call_rcu(&ev_fd->rcu, io_eventfd_put);
> +		ret = 0;
> +		goto out;
>  	}
> +	ret = -ENXIO;
>  
> -	return -ENXIO;
> +out:
> +	mutex_unlock(&ctx->ev_fd_lock);
> +	return ret;
>  }

I also think that'd be cleaner without the goto:

{
	struct io_ev_fd *ev_fd;
	int ret;

	mutex_lock(&ctx->ev_fd_lock);
	ev_fd = rcu_dereference_protected(ctx->io_ev_fd,
					lockdep_is_held(&ctx->ev_fd_lock));
	if (ev_fd) {
		call_rcu(&ev_fd->rcu, io_eventfd_put);
		mutex_unlock(&ctx->ev_fd_lock);
		return 0;
	}

	mutex_unlock(&ctx->ev_fd_lock);
	return -ENXIO;
}

-- 
Jens Axboe

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