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Date:   Tue, 29 Mar 2022 09:15:46 +0800
From:   Muchun Song <songmuchun@...edance.com>
To:     Roman Gushchin <roman.gushchin@...ux.dev>
Cc:     Waiman Long <longman@...hat.com>,
        Andrew Morton <akpm@...ux-foundation.org>,
        Linux Memory Management List <linux-mm@...ck.org>,
        LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH-mm v3] mm/list_lru: Optimize memcg_reparent_list_lru_node()

On Tue, Mar 29, 2022 at 3:12 AM Roman Gushchin <roman.gushchin@...ux.dev> wrote:
>
> On Sun, Mar 27, 2022 at 08:57:15PM -0400, Waiman Long wrote:
> > On 3/22/22 22:12, Muchun Song wrote:
> > > On Wed, Mar 23, 2022 at 9:55 AM Waiman Long <longman@...hat.com> wrote:
> > > > On 3/22/22 21:06, Muchun Song wrote:
> > > > > On Wed, Mar 9, 2022 at 10:40 PM Waiman Long <longman@...hat.com> wrote:
> > > > > > Since commit 2c80cd57c743 ("mm/list_lru.c: fix list_lru_count_node()
> > > > > > to be race free"), we are tracking the total number of lru
> > > > > > entries in a list_lru_node in its nr_items field.  In the case of
> > > > > > memcg_reparent_list_lru_node(), there is nothing to be done if nr_items
> > > > > > is 0.  We don't even need to take the nlru->lock as no new lru entry
> > > > > > could be added by a racing list_lru_add() to the draining src_idx memcg
> > > > > > at this point.
> > > > > Hi Waiman,
> > > > >
> > > > > Sorry for the late reply.  Quick question: what if there is an inflight
> > > > > list_lru_add()?  How about the following race?
> > > > >
> > > > > CPU0:                               CPU1:
> > > > > list_lru_add()
> > > > >       spin_lock(&nlru->lock)
> > > > >       l = list_lru_from_kmem(memcg)
> > > > >                                       memcg_reparent_objcgs(memcg)
> > > > >                                       memcg_reparent_list_lrus(memcg)
> > > > >                                           memcg_reparent_list_lru()
> > > > >                                               memcg_reparent_list_lru_node()
> > > > >                                                   if (!READ_ONCE(nlru->nr_items))
> > > > >                                                       // Miss reparenting
> > > > >                                                       return
> > > > >       // Assume 0->1
> > > > >       l->nr_items++
> > > > >       // Assume 0->1
> > > > >       nlru->nr_items++
> > > > >
> > > > > IIUC, we use nlru->lock to serialise this scenario.
> > > > I guess this race is theoretically possible but very unlikely since it
> > > > means a very long pause between list_lru_from_kmem() and the increment
> > > > of nr_items.
> > > It is more possible in a VM.
> > >
> > > > How about the following changes to make sure that this race can't happen?
> > > >
> > > > diff --git a/mm/list_lru.c b/mm/list_lru.c
> > > > index c669d87001a6..c31a0a8ad4e7 100644
> > > > --- a/mm/list_lru.c
> > > > +++ b/mm/list_lru.c
> > > > @@ -395,9 +395,10 @@ static void memcg_reparent_list_lru_node(struct
> > > > list_lru *lru, int nid,
> > > >           struct list_lru_one *src, *dst;
> > > >
> > > >           /*
> > > > -        * If there is no lru entry in this nlru, we can skip it
> > > > immediately.
> > > > +        * If there is no lru entry in this nlru and the nlru->lock is free,
> > > > +        * we can skip it immediately.
> > > >            */
> > > > -       if (!READ_ONCE(nlru->nr_items))
> > > > +       if (!READ_ONCE(nlru->nr_items) && !spin_is_locked(&nlru->lock))
> > > I think we also should insert a smp_rmb() between those two loads.
> >
> > Thinking about this some more, I believe that adding spin_is_locked() check
> > will be enough for x86. However, that will likely not be enough for arches
> > with a more relaxed memory semantics. So the safest way to avoid this
> > possible race is to move the check to within the lock critical section,
> > though that comes with a slightly higher overhead for the 0 nr_items case. I
> > will send out a patch to correct that. Thanks for bring this possible race
> > to my attention.
>
> Yes, I think it's not enough:

I think it may be enough if we insert a smp_rmb() between those two loads.

> CPU0                                       CPU1
> READ_ONCE(&nlru->nr_items) -> 0
>                                            spin_lock(&nlru->lock);
>                                            nlru->nr_items++;
                                             ^^^
                                             |||
                                             The nlr here is not the
same as the one in CPU0,
                                             since CPU0 have done the
memcg reparting. Then
                                             CPU0 will not miss nlru
reparting.  If I am wrong, please
                                             correct me.  Thanks.
>                                            spin_unlock(&nlru->lock);
> && !spin_is_locked(&nlru->lock) -> 0

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