linux-kernel - Re: [PATCH v2 07/28] lib/printbuf: Unit specifiers

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Message-ID: <YoayjKMjhRVCiKKl@casper.infradead.org>
Date:   Thu, 19 May 2022 22:11:40 +0100
From:   Matthew Wilcox <willy@...radead.org>
To:     Kent Overstreet <kent.overstreet@...il.com>
Cc:     Andy Shevchenko <andriy.shevchenko@...ux.intel.com>,
        linux-kernel@...r.kernel.org, linux-mm@...r.kernel.org,
        pmladek@...e.com, rostedt@...dmis.org, senozhatsky@...omium.org
Subject: Re: [PATCH v2 07/28] lib/printbuf: Unit specifiers

On Thu, May 19, 2022 at 04:26:26PM -0400, Kent Overstreet wrote:
> On Thu, May 19, 2022 at 11:21:41PM +0300, Andy Shevchenko wrote:
> > On Thu, May 19, 2022 at 01:24:00PM -0400, Kent Overstreet wrote:
> > > +void pr_human_readable_s64(struct printbuf *buf, s64 v)
> > > +{
> > > +	if (v < 0)
> > > +		pr_char(buf, '-');
> > > +	pr_human_readable_u64(buf, abs(v));
> > 
> > Wouldn't -v work?
> 
> This is a bit terser

How about:

	if (v < 0) {
		pr_char(buf, '-');
		v = -v;
	}
	pr_human_readable_u64(buf, v);

(some pedantic compilers might warn about the behaviour of S64_MIN, but
I think we're OK)

> > > + * pr_human_readable_u64 - Print out a u64 according to printbuf unit options
> > 
> > Have you ever compile this? We have kernel doc validator running when compiling
> > the code...
> 
> Yes I have, but I've never seen the kernel doc validator - can you point me to
> something so I can get that working?

You have to run 'make W=1' to get it, so Andy is being a bit overly
harsh here.  Most people use neither W=1, nor C=1.