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Message-Id: <20220613094925.262644048@linuxfoundation.org>
Date: Mon, 13 Jun 2022 12:09:38 +0200
From: Greg Kroah-Hartman <gregkh@...uxfoundation.org>
To: linux-kernel@...r.kernel.org
Cc: Greg Kroah-Hartman <gregkh@...uxfoundation.org>,
stable@...r.kernel.org,
Alexander Lobakin <alexandr.lobakin@...el.com>,
Petr Mladek <pmladek@...e.com>,
Masahiro Yamada <masahiroy@...nel.org>,
Sasha Levin <sashal@...nel.org>
Subject: [PATCH 5.15 076/247] modpost: fix removing numeric suffixes
From: Alexander Lobakin <alexandr.lobakin@...el.com>
[ Upstream commit b5beffa20d83c4e15306c991ffd00de0d8628338 ]
With the `-z unique-symbol` linker flag or any similar mechanism,
it is possible to trigger the following:
ERROR: modpost: "param_set_uint.0" [vmlinux] is a static EXPORT_SYMBOL
The reason is that for now the condition from remove_dot():
if (m && (s[n + m] == '.' || s[n + m] == 0))
which was designed to test if it's a dot or a '\0' after the suffix
is never satisfied.
This is due to that `s[n + m]` always points to the last digit of a
numeric suffix, not on the symbol next to it (from a custom debug
print added to modpost):
param_set_uint.0, s[n + m] is '0', s[n + m + 1] is '\0'
So it's off-by-one and was like that since 2014.
Fix this for the sake of any potential upcoming features, but don't
bother stable-backporting, as it's well hidden -- apart from that
LD flag, it can be triggered only with GCC LTO which never landed
upstream.
Fixes: fcd38ed0ff26 ("scripts: modpost: fix compilation warning")
Signed-off-by: Alexander Lobakin <alexandr.lobakin@...el.com>
Reviewed-by: Petr Mladek <pmladek@...e.com>
Signed-off-by: Masahiro Yamada <masahiroy@...nel.org>
Signed-off-by: Sasha Levin <sashal@...nel.org>
---
scripts/mod/modpost.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/scripts/mod/modpost.c b/scripts/mod/modpost.c
index ca491aa2b376..7a5bddb8913e 100644
--- a/scripts/mod/modpost.c
+++ b/scripts/mod/modpost.c
@@ -1971,7 +1971,7 @@ static char *remove_dot(char *s)
if (n && s[n]) {
size_t m = strspn(s + n + 1, "0123456789");
- if (m && (s[n + m] == '.' || s[n + m] == 0))
+ if (m && (s[n + m + 1] == '.' || s[n + m + 1] == 0))
s[n] = 0;
/* strip trailing .lto */
--
2.35.1
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