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Message-ID: <CAHp75VdXGJtPd_oZPGkS1=DoWjFYxbQu_7Vtfj547QQkpz2KNA@mail.gmail.com>
Date: Thu, 14 Jul 2022 12:15:58 +0200
From: Andy Shevchenko <andy.shevchenko@...il.com>
To: ChiaEn Wu <peterwu.pub@...il.com>
Cc: Lee Jones <lee.jones@...aro.org>,
Daniel Thompson <daniel.thompson@...aro.org>,
Jingoo Han <jingoohan1@...il.com>, Pavel Machek <pavel@....cz>,
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szuni chen <szunichen@...il.com>
Subject: Re: [PATCH v4 13/13] video: backlight: mt6370: Add Mediatek MT6370 support
On Thu, Jul 14, 2022 at 11:43 AM Andy Shevchenko
<andy.shevchenko@...il.com> wrote:
> On Thu, Jul 14, 2022 at 11:27 AM Andy Shevchenko
> <andy.shevchenko@...il.com> wrote:
> > On Thu, Jul 14, 2022 at 9:13 AM ChiaEn Wu <peterwu.pub@...il.com> wrote:
> > > Andy Shevchenko <andy.shevchenko@...il.com> 於 2022年7月13日 週三 晚上8:07寫道:
...
> > > * prop_val = 1 --> 1 steps --> b'00
> > > * prop_val = 2 ~ 4 --> 4 steps --> b'01
> > > * prop_val = 5 ~ 16 --> 16 steps --> b'10
> > > * prop_val = 17 ~ 64 --> 64 steps --> b'11
> >
> > So, for 1 --> 0, for 2 --> 1, for 5 --> 2, and for 17 --> 3.
> > Now, consider x - 1:
> > 0 ( 0 ) --> 0
> > 1 (2^0) --> 1
> > 4 (2^2) --> 2
> > 16 (2^4) --> 3
> > 64 (2^6) --> ? (but let's consider that the range has been checked already)
> >
> > Since we take the lower limit, it means ffs():
> >
> > y = (ffs(x - 1) + 1) / 2;
> >
> > Does it work for you?
>
> It wouldn't, because we need to use fls() against it actually.
>
> So,
> 0..1 (-1..0) --> 0
> 2..4 (1..3) --> 1
> 5..16 (4..15) --> 2
> 17..64 (16..63) --> 3
>
> y = x ? ((fls(x - 1) + 1) / 2 : 0;
Okay, I nailed it down, but Daniel is right, it's simpler to have just
conditionals.
y = x >=2 ? __fls(x - 1) / 2 + 1 : 0;
--
With Best Regards,
Andy Shevchenko
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