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Message-ID: <YxdZlCly2ad1rtcI@nvidia.com>
Date: Tue, 6 Sep 2022 11:30:44 -0300
From: Jason Gunthorpe <jgg@...dia.com>
To: David Hildenbrand <david@...hat.com>
Cc: John Hubbard <jhubbard@...dia.com>, Yang Shi <shy828301@...il.com>,
peterx@...hat.com, kirill.shutemov@...ux.intel.com,
hughd@...gle.com, akpm@...ux-foundation.org, linux-mm@...ck.org,
linux-kernel@...r.kernel.org
Subject: Re: [PATCH] mm: gup: fix the fast GUP race against THP collapse
On Tue, Sep 06, 2022 at 03:57:30PM +0200, David Hildenbrand wrote:
> > READ_ONCE primarily is a marker that the data being read is unstable
> > and that the compiler must avoid all instability when reading it. eg
> > in this case the compiler could insanely double read the value, even
> > though the 'if' requires only a single read. This would result in
> > corrupt calculation.
>
> As we have a full memory barrier + compile barrier, the compiler might
> indeed do double reads and all that stuff. BUT, it has to re-read after we
> incremented the refcount, and IMHO that's the important part to detect the
> change.
Yes, it is important, but it is not the only important part.
The compiler still has to exectute "if (*a != b)" *correctly*.
This is what READ_ONCE is for. It doesn't set order, it doesn't
implement a barrier, it tells the compiler that '*a' is unstable data
and the compiler cannot make assumptions based on the idea that
reading '*a' multiple times will always return the same value.
If the compiler makes those assumptions then maybe even though 'if (*a
!= b)' is the reality, it could mis-compute '*a == b'. You enter into
undefined behavior here.
Though it is all very unlikely, the general memory model standard is
to annotate with READ_ONCE.
Jason
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