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Message-ID: <xhsmhbkorl3tr.mognet@vschneid.remote.csb> Date: Mon, 28 Nov 2022 11:24:16 +0000 From: Valentin Schneider <vschneid@...hat.com> To: Tejun Heo <tj@...nel.org> Cc: linux-kernel@...r.kernel.org, Lai Jiangshan <jiangshanlai@...il.com>, Peter Zijlstra <peterz@...radead.org>, Frederic Weisbecker <frederic@...nel.org>, Juri Lelli <juri.lelli@...hat.com>, Phil Auld <pauld@...hat.com>, Marcelo Tosatti <mtosatti@...hat.com> Subject: Re: [PATCH v5 3/5] workqueue: Make too_many_workers() return the worker excess On 22/11/22 10:17, Tejun Heo wrote: > Hello, > > On Tue, Nov 22, 2022 at 07:29:35PM +0000, Valentin Schneider wrote: > ... >> The function currently returns true when >> (nr_idle - 2) * MAX_IDLE_WORKERS_RATIO >= nr_busy >> thus, the desired number of idle workers is expressed by >> (nr_idle - 2) * MAX_IDLE_WORKERS_RATIO == nr_busy - 1 >> IOW >> nr_idle == ((nr_busy - 1) / MAX_IDLE_WORKERS_RATIO) + 2 >> +/* How many idle workers should we get rid of, if any? */ >> +static unsigned int worker_cull_count(struct worker_pool *pool) > > Can we name it nr_workers_to_cull()? > Ack >> { >> bool managing = pool->flags & POOL_MANAGER_ACTIVE; >> int nr_idle = pool->nr_idle + managing; /* manager is considered idle */ >> int nr_busy = pool->nr_workers - nr_idle; >> >> - return nr_idle > 2 && (nr_idle - 2) * MAX_IDLE_WORKERS_RATIO >= nr_busy; >> + lockdep_assert_held(&pool->lock); >> + >> + /* >> + * We keep at least 2 spare idle workers, but overall aim to keep at >> + * most (1 / MAX_IDLE_WORKERS_RATIO) workers idle. >> + */ >> + return max(0, nr_idle - 2 - ((nr_busy - 1) / MAX_IDLE_WORKERS_RATIO)); > > I think we can do away with the subtraction on nr_busy. I don't think it'd > make any material difference, so maybe we can do: > > return max(0, nr_idle - 2 - nr_busy / MAX_IDLE_WORKERS_RATIO); > I'll do that if this survives in the next revision :) > Thanks. > > -- > tejun
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