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Message-ID: <d7bb31547e9bbf6684801a7bbd857810@umbiko.net>
Date: Sat, 24 Dec 2022 12:39:15 +0000
From: Andreas Ziegler <br015@...iko.net>
To: Daniel Bristot de Oliveira <bristot@...nel.org>,
Steven Rostedt <rostedt@...dmis.org>
Cc: linux-trace-devel@...r.kernel.org, linux-kernel@...r.kernel.org
Subject: rtla osnoise hist: average duration is always zero
-- Observed in, but not limited to, Linux 6.1.1
Dear all,
rtla osnoise hist always outputs '0' as average duration value. Example:
# rtla osnoise hist -P F:1 -c 0-1 -r 900000 -d 1M -b 1 -E 5000 -T 1
# RTLA osnoise histogram
# Time unit is microseconds (us)
# Duration: 0 00:01:00
...
count: 5629 1364
min: 1 1
avg: 0 0
max: 2955 56
This is due to sum_sample in osnoise_hist_update_multiple() being
calculated as the sum (duration), not as sum (duration * count).
Rounding, instead of truncating, of the average value would be cool.
The following patch would solve the issue described above:
Sampled duration must be weighted by observed quantity, to arrive at a
correct average duration value.
Fix calculation of total duration by summing (duration * count).
Introduce rounding for calculation of final value.
Signed-off-by: Andreas Ziegler <br015@...iko.net>
--- a/tools/tracing/rtla/src/osnoise_hist.c
+++ b/tools/tracing/rtla/src/osnoise_hist.c
@@ -121,6 +121,7 @@
{
struct osnoise_hist_params *params = tool->params;
struct osnoise_hist_data *data = tool->data;
+ unsigned long long total_duration;
int entries = data->entries;
int bucket;
int *hist;
@@ -131,10 +132,12 @@
if (data->bucket_size)
bucket = duration / data->bucket_size;
+ total_duration = duration * count;
+
hist = data->hist[cpu].samples;
data->hist[cpu].count += count;
update_min(&data->hist[cpu].min_sample, &duration);
- update_sum(&data->hist[cpu].sum_sample, &duration);
+ update_sum(&data->hist[cpu].sum_sample, &total_duration);
update_max(&data->hist[cpu].max_sample, &duration);
if (bucket < entries)
@@ -333,7 +336,7 @@
if (data->hist[cpu].count)
trace_seq_printf(trace->seq, "%9llu ",
- data->hist[cpu].sum_sample / data->hist[cpu].count);
+ (data->hist[cpu].sum_sample + data->hist[cpu].count / 2) /
data->hist[cpu].count);
else
trace_seq_printf(trace->seq, " - ");
}
Kind regards,
Andreas
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