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Date:   Sat, 11 Feb 2023 22:35:44 -0500
From:   Joel Fernandes <joel@...lfernandes.org>
To:     Alan Stern <stern@...land.harvard.edu>
Cc:     "Paul E. McKenney" <paulmck@...nel.org>,
        linux-kernel@...r.kernel.org, linux-arch@...r.kernel.org,
        kernel-team@...a.com, mingo@...nel.org, parri.andrea@...il.com,
        will@...nel.org, peterz@...radead.org, boqun.feng@...il.com,
        npiggin@...il.com, dhowells@...hat.com, j.alglave@....ac.uk,
        luc.maranget@...ia.fr, akiyks@...il.com
Subject: Re: Current LKMM patch disposition



> On Feb 11, 2023, at 9:59 PM, Alan Stern <stern@...land.harvard.edu> wrote:
> 
> On Sat, Feb 11, 2023 at 07:30:32PM -0500, Joel Fernandes wrote:
>>> On Sat, Feb 11, 2023 at 3:19 PM Alan Stern <stern@...land.harvard.edu> wrote:
>>> The idea is that the value returned by srcu_read_lock() can be stored to
>>> and loaded from a sequence (possibly of length 0) of variables, and the
>>> final load gets fed to srcu_read_unlock().  That's what the original
>>> version of the code expresses.
>> 
>> Now I understand it somewhat, and I see where I went wrong. Basically,
>> you were trying to sequence zero or one "data + rf sequence" starting
>> from lock and unlock with a final "data" sequence. That data sequence
>> can be between the srcu-lock and srcu-unlock itself, in case where the
>> lock/unlock happened on the same CPU.
> 
> In which case the sequence has length 0.  Exactly right.

Got it.

> 
>> Damn, that's really complicated.. and I still don't fully understand it.
> 
> It sounds like you've made an excellent start.  :-)

Thanks. :-)

> 
>> In trying to understand your CAT code, I made some assumptions about
>> your formulas by reverse engineering the CAT code with the tests,
>> which is kind of my point that it is extremely hard to read CAT. That
> 
> I can't argue against that; it _is_ hard.  It helps to have had the 
> right kind of training beforehand (my degree was in mathematical logic).

Got it, I am reviewing the academic material on these as well.

>> is kind of why I want to understand the CAT, because for me
>> explanation.txt is too much at a higher level to get a proper
>> understanding of the memory model.. I tried re-reading explanation.txt
>> many times.. then I realized I am just rewriting my own condensed set
>> of notes every few months.
> 
> Would you like to post a few examples showing some of the most difficult 
> points you encountered?  Maybe explanation.txt can be improved.

Sure, I will share some things I faced difficult with, tomorrow or so. Off the top, cumulativity was certainly pretty hard to parse.

> 
>>> I'm not sure that breaking this relation up into pieces will make it any
>>> easier to understand.
>> 
>> Yes, but I tried. I will keep trying to understand your last patch
>> more. Especially I am still not sure, why in the case of an SRCU
>> reader on a single CPU, the following does not work:
>> let srcu-rscs = ([Srcu-lock]; data; [Srcu-unlock]).
> 
> You have to understand that herd7 does not track dependencies through 
> stores and subsequent loads.  That is, if you have something like:
> 
>    r1 = READ_ONCE(*x);
>    WRITE_ONCE(*y, r1);
>    r2 = READ_ONCE(*y);
>    WRITE_ONCE(*z, r2);
> 
> then herd7 will realize that the write to y depends on the value read 
> from x, and it will realize that the write to z depends on the value 
> read from y.  But it will not realize that the write to z depends on the 
> value read from x; it loses track of that dependency because of the 
> intervening store/load from y.
> 
> More to the point, if you have:
> 
>    r1 = srcu_read_lock(lock);
>    WRITE_ONCE(*y, r1);
>    r2 = READ_ONCE(*y);
>    srcu_read_unlock(lock, r2);
> 
> then herd7 will not realize that the value of r2 depends on the value of 
> r1.  So there will be no data dependency from the srcu_read_lock() to 
> the srcu_read_unlock().

Got it!  Now I understand why the intermediate load stores needs to be modeled with your carry-srcu-data formula, even on the same CPU! Thank you so much Alan!!

Thanks,

 - Joel

> 
> Alan

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