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Message-ID: <b456ea7c-18be-3397-0115-fa25007741bf@intel.com>
Date: Thu, 8 Jun 2023 16:43:43 -0700
From: Dave Hansen <dave.hansen@...el.com>
To: kirill.shutemov@...ux.intel.com, Kai Huang <kai.huang@...el.com>
Cc: linux-kernel@...r.kernel.org, kvm@...r.kernel.org,
linux-mm@...ck.org, tony.luck@...el.com, peterz@...radead.org,
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david@...hat.com, dan.j.williams@...el.com,
rafael.j.wysocki@...el.com, ying.huang@...el.com,
reinette.chatre@...el.com, len.brown@...el.com, ak@...ux.intel.com,
isaku.yamahata@...el.com, chao.gao@...el.com,
sathyanarayanan.kuppuswamy@...ux.intel.com, bagasdotme@...il.com,
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Subject: Re: [PATCH v11 12/20] x86/virt/tdx: Allocate and set up PAMTs for
TDMRs
On 6/8/23 16:24, kirill.shutemov@...ux.intel.com wrote:
>> ret = -EINVAL;
>> + if (ret)
>> + tdmrs_free_pamt_all(&tdx_tdmr_list);
>> + else
>> + pr_info("%lu KBs allocated for PAMT.\n",
>> + tdmrs_count_pamt_pages(&tdx_tdmr_list) * 4);
> "* 4"? This is very cryptic. procfs uses "<< (PAGE_SHIFT - 10)" which
> slightly less magic to me. And just make the helper that returns kilobytes
> to begin with, if it is the only caller.
Let's look at where this data comes from:
+static unsigned long tdmrs_count_pamt_pages(struct tdmr_info_list
*tdmr_list)
+{
+ unsigned long pamt_npages = 0;
+ int i;
+
+ for (i = 0; i < tdmr_list->nr_consumed_tdmrs; i++) {
+ unsigned long pfn, npages;
+
+ tdmr_get_pamt(tdmr_entry(tdmr_list, i), &pfn, &npages);
+ pamt_npages += npages;
+ }
OK, so tdmr_get_pamt() is getting it in pages. How is it *stored*?
+static void tdmr_get_pamt(struct tdmr_info *tdmr, unsigned long *pamt_pfn,
+ unsigned long *pamt_npages)
+{
...
+ pamt_sz = tdmr->pamt_4k_size + tdmr->pamt_2m_size + tdmr->pamt_1g_size;
++ *pamt_pfn = PHYS_PFN(pamt_base);
+ *pamt_npages = pamt_sz >> PAGE_SHIFT;
+}
Oh, it's actually stored in bytes. So to print it out you actually
convert it from bytes->pages->kbytes. Not the best.
If tdmr_get_pamt() just returned 'pamt_size_bytes', you could do one
conversion at:
free_contig_range(pamt_pfn, pamt_size_bytes >> PAGE_SIZE);
and since tdmrs_count_pamt_pages() has only one caller you can just make
it: tdmrs_count_pamt_kb(). The print becomes:
pr_info("%lu KBs allocated for PAMT.\n",
tdmrs_count_pamt_kb(&tdx_tdmr_list) * 4);
and tdmrs_count_pamt_kb() does something super fancy like:
return pamt_size_bytes / 1024;
which makes total complete obvious sense and needs zero explanation.
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