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Message-ID: <dec6b647-5ff2-4c57-8b10-b2d5c544566a@intel.com>
Date: Tue, 26 Dec 2023 16:44:03 +0800
From: Yi Liu <yi.l.liu@...el.com>
To: "Tian, Kevin" <kevin.tian@...el.com>, "joro@...tes.org" <joro@...tes.org>,
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Subject: Re: [PATCH v7 7/9] iommu/vt-d: Allow qi_submit_sync() to return the
QI faults
On 2023/12/26 14:15, Yi Liu wrote:
>
>
> On 2023/12/26 12:13, Tian, Kevin wrote:
>>> From: Liu, Yi L <yi.l.liu@...el.com>
>>> Sent: Tuesday, December 26, 2023 12:03 PM
>>>
>>> On 2023/12/22 12:23, Tian, Kevin wrote:
>>>>> From: Liu, Yi L <yi.l.liu@...el.com>
>>>>> Sent: Thursday, December 21, 2023 11:40 PM
>>>>>
>>>>> + fault &= DMA_FSTS_IQE | DMA_FSTS_ITE | DMA_FSTS_ICE;
>>>>> + if (fault) {
>>>>> + if (fsts)
>>>>> + *fsts |= fault;
>>>>
>>>> do we expect the fault to be accumulated? otherwise it's clearer to
>>>> just do direct assignment instead of asking for the caller to clear
>>>> the variable before invocation.
>>>
>>> not quite get. do you mean the fault should not be cleared in the caller
>>> side?
>>>
>>
>> I meant:
>>
>> if (fsts)
>> *fsts = fault;
>>
>> unless there is a reason to *OR* the original value.
>
> I guess no such a reason. :) let me modify it.
hmmm, replied too soon. The qi_check_fault() would be called multiple
times in one invalidation circle as qi_submit_sync() needs to see if any
fault happened before the hw writes back QI_DONE to the wait descriptor.
There can be ICE which may eventually result in ITE. So caller of
qi_check_fault()
would continue to wait for QI_DONE. So qi_check_fault() returns 0 to let
qi_submit_sync() go on though ICE detected. If we use '*fsts = fault;',
then ICE would be missed since the input fsts pointer is the same in
one qi_submit_sync() call.
--
Regards,
Yi Liu
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