[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]
Message-Id: <20240416-kgdb_read_refactor-v1-5-b18c2d01076d@linaro.org>
Date: Tue, 16 Apr 2024 11:43:22 +0100
From: Daniel Thompson <daniel.thompson@...aro.org>
To: Jason Wessel <jason.wessel@...driver.com>,
Douglas Anderson <dianders@...omium.org>
Cc: kgdb-bugreport@...ts.sourceforge.net, linux-kernel@...r.kernel.org
Subject: [PATCH 5/7] kdb: Merge identical case statements in kdb_read()
The code that handles case 14 (down) and case 16 (up) has been copy and
pasted despite being byte-for-byte identical. Combine them.
Signed-off-by: Daniel Thompson <daniel.thompson@...aro.org>
---
kernel/debug/kdb/kdb_io.c | 10 +---------
1 file changed, 1 insertion(+), 9 deletions(-)
diff --git a/kernel/debug/kdb/kdb_io.c b/kernel/debug/kdb/kdb_io.c
index df7b5eb52d74f..08a86a329eb64 100644
--- a/kernel/debug/kdb/kdb_io.c
+++ b/kernel/debug/kdb/kdb_io.c
@@ -294,6 +294,7 @@ static char *kdb_read(char *buffer, size_t bufsize)
}
break;
case 14: /* Down */
+ case 16: /* Up */
memset(tmpbuffer, ' ',
strlen(kdb_prompt_str) + (lastchar-buffer));
*(tmpbuffer+strlen(kdb_prompt_str) +
@@ -308,15 +309,6 @@ static char *kdb_read(char *buffer, size_t bufsize)
++cp;
}
break;
- case 16: /* Up */
- memset(tmpbuffer, ' ',
- strlen(kdb_prompt_str) + (lastchar-buffer));
- *(tmpbuffer+strlen(kdb_prompt_str) +
- (lastchar-buffer)) = '\0';
- kdb_printf("\r%s\r", tmpbuffer);
- *lastchar = (char)key;
- *(lastchar+1) = '\0';
- return lastchar;
case 9: /* Tab */
if (tab < 2)
++tab;
--
2.43.0
Powered by blists - more mailing lists