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Message-ID: <87jzdq26id.ffs@tglx>
Date: Tue, 29 Oct 2024 17:55:38 +0100
From: Thomas Gleixner <tglx@...utronix.de>
To: Frederic Weisbecker <frederic@...nel.org>
Cc: LKML <linux-kernel@...r.kernel.org>, Anna-Maria Behnsen
<anna-maria@...utronix.de>, John Stultz <jstultz@...gle.com>, Peter
Zijlstra <peterz@...radead.org>, Ingo Molnar <mingo@...nel.org>, Stephen
Boyd <sboyd@...nel.org>, Eric Biederman <ebiederm@...ssion.com>, Oleg
Nesterov <oleg@...hat.com>
Subject: Re: [patch V5 16/26] signal: Replace resched_timer logic
On Tue, Oct 29 2024 at 17:34, Frederic Weisbecker wrote:
> Le Tue, Oct 29, 2024 at 05:22:17PM +0100, Thomas Gleixner a écrit :
>> On Tue, Oct 29 2024 at 16:56, Frederic Weisbecker wrote:
>> >> @@ -568,10 +568,10 @@ static void collect_signal(int sig, stru
>> >> list_del_init(&first->list);
>> >> copy_siginfo(info, &first->info);
>> >>
>> >> - *resched_timer = (first->flags & SIGQUEUE_PREALLOC) &&
>> >> - (info->si_code == SI_TIMER);
>> >> -
>> >> - __sigqueue_free(first);
>> >> + if (unlikely((first->flags & SIGQUEUE_PREALLOC) && (info->si_code == SI_TIMER)))
>> >> + *timer_sigq = first;
>> >> + else
>> >> + __sigqueue_free(first);
>> >
>> > So this isn't calling __sigqueue_free() unconditionally anymore. What if
>> > the timer has been freed already, what is going to free the sigqueue?
>>
>> __sigqueue_free() does not free timers marked with SIGQUEUE_PREALLOC.
>>
>> sigqueue_free() takes care of that, which is invoked from
>> posixtimer_free_timer(). It clears SIGQUEUE_PREALLOC and if it is queued
>> it lets it pending and delivery will free it.
>
> But the delivery freeing used to be done with the __sigqueue_free()
> above, which doesn't happen anymore, right?
It still happens because SIGQUEUE_PREALLOC is cleared in sigqueue_free()
__sigqueue_free() has
if (q->flags & PREALLOC)
return;
So the old code called __sigqueue_free() unconditionally which just
returned. But now we have a condition to that effect already, so why
call into __sigqueue_free() for nothing?
Let me add a comment.
Thanks,
tglx
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