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Message-ID: <2025011641-seventeen-curse-e404@gregkh>
Date: Thu, 16 Jan 2025 10:51:33 +0100
From: Greg KH <gregkh@...uxfoundation.org>
To: Tuo Li <islituo@...il.com>
Cc: tomas.winkler@...el.com, arnd@...db.de,
LKML <linux-kernel@...r.kernel.org>,
Jia-Ju Bai <baijiaju1990@...il.com>
Subject: Re: [BUG] mei: a possible use-after-free caused by concurrency
execution
On Thu, Jan 16, 2025 at 05:26:33PM +0800, Tuo Li wrote:
> Hello,
>
> Our static analysis tool has identified a potential use-after-free caused
> by concurrency execution in drivers/misc/mei/main.c.
>
> Consider the following execution scenario:
> (The line numbers can be referred to
> https://elixir.bootlin.com/linux/v6.12/source/drivers/misc/mei/main.c)
>
> mei_release() //Line 112
> cl = file->private_data; //Line 114
> mutex_lock(&dev->device_lock); //Line 123
> kfree(cl); //Line 149
> file->private_data = NULL; //Line 152
> mutex_unlock(&dev->device_lock); //Line 154
>
> mei_read() //Line 169
> cl = file->private_data; //Line 172
> mutex_lock(&dev->device_lock); //Line 184
> cb = mei_cl_read_cb(cl, file); //Line 200
> cl_dbg(dev, cl, ...); //Line 275
> mutex_unlock(&dev->device_lock); //Line 276
>
> If mei_release() and mei_read() can execute concurrently and the execution
> order is 114, 172, 123, 149 (free), 152, 154, 184, 200 (use), 275 (use),
> 276, a possible use-after-free can occur.
How can release run at the same time read happens? release only happens
after all references are dropped, right?
> Our static analysis tool reports this use-after-free when analyzing Linux
> 6.12. The tool deduces lock() and unlock() pairs with alias analysis. It
> then applies data flow analysis to detect use-after-free across
> synchronization points.
>
> I am not quite sure whether this possible use-after-free is real and how to
> fix it if it is real.
Test it and see! And if you feel a fix is needed, please provide a
patch.
thanks,
greg k-h
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