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Message-Id: <20250129.153120.170416639063888853.fujita.tomonori@gmail.com>
Date: Wed, 29 Jan 2025 15:31:20 +0900 (JST)
From: FUJITA Tomonori <fujita.tomonori@...il.com>
To: fujita.tomonori@...il.com
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Subject: Re: [PATCH v9 7/8] rust: Add read_poll_timeout functions
On Tue, 28 Jan 2025 15:29:57 +0900 (JST)
FUJITA Tomonori <fujita.tomonori@...il.com> wrote:
> On Tue, 28 Jan 2025 08:49:37 +0800
> Gary Guo <gary@...yguo.net> wrote:
>
>> On Mon, 27 Jan 2025 15:31:47 +0900 (JST)
>> FUJITA Tomonori <fujita.tomonori@...il.com> wrote:
>>
>>> On Mon, 27 Jan 2025 11:46:46 +0800
>>> Gary Guo <gary@...yguo.net> wrote:
>>>
>>> >> +#[track_caller]
>>> >> +pub fn read_poll_timeout<Op, Cond, T: Copy>(
>>> >> + mut op: Op,
>>> >> + mut cond: Cond,
>>> >> + sleep_delta: Delta,
>>> >> + timeout_delta: Delta,
>>> >> +) -> Result<T>
>>> >> +where
>>> >> + Op: FnMut() -> Result<T>,
>>> >> + Cond: FnMut(&T) -> bool,
>>> >> +{
>>> >> + let start = Instant::now();
>>> >> + let sleep = !sleep_delta.is_zero();
>>> >> + let timeout = !timeout_delta.is_zero();
>>> >> +
>>> >> + if sleep {
>>> >> + might_sleep(Location::caller());
>>> >> + }
>>> >> +
>>> >> + loop {
>>> >> + let val = op()?;
>>> >> + if cond(&val) {
>>> >> + // Unlike the C version, we immediately return.
>>> >> + // We know the condition is met so we don't need to check again.
>>> >> + return Ok(val);
>>> >> + }
>>> >> + if timeout && start.elapsed() > timeout_delta {
>>> >
>>> > Re-reading this again I wonder if this is the desired behaviour? Maybe
>>> > a timeout of 0 should mean check-once instead of no timeout. The
>>> > special-casing of 0 makes sense in C but in Rust we should use `None`
>>> > to mean it instead?
>>>
>>> It's the behavior of the C version; the comment of this function says:
>>>
>>> * @timeout_us: Timeout in us, 0 means never timeout
>>>
>>> You meant that waiting for a condition without a timeout is generally
>>> a bad idea? If so, can we simply return EINVAL for zero Delta?
>>>
>>
>> No, I think we should still keep the ability to represent indefinite
>> wait (no timeout) but we should use `None` to represent this rather
>> than `Delta::ZERO`.
>>
>> I know that we use 0 to mean indefinite wait in C, I am saying that
>> it's not the most intuitive way to represent in Rust.
>>
>> Intuitively, a timeout of 0 should be closer to a timeout of 1 and thus
>> should mean "return with ETIMEDOUT immedidately" rather than "wait
>> forever".
>>
>> In C since we don't have a very good sum type support, so we
>> special case 0 to be the special value to represent indefinite wait,
>> but I don't think we need to repeat this in Rust.
>
> Understood, thanks. How about the following code?
>
> +#[track_caller]
> +pub fn read_poll_timeout<Op, Cond, T: Copy>(
Oops, `Copy` should be dropped:
+pub fn read_poll_timeout<Op, Cond, T>(
> + mut op: Op,
> + mut cond: Cond,
> + sleep_delta: Delta,
> + timeout_delta: Option<Delta>,
> +) -> Result<T>
> +where
> + Op: FnMut() -> Result<T>,
> + Cond: FnMut(&T) -> bool,
> +{
> + let start = Instant::now();
> + let sleep = !sleep_delta.is_zero();
> +
> + if sleep {
> + might_sleep(Location::caller());
> + }
> +
> + loop {
> + let val = op()?;
> + if cond(&val) {
> + // Unlike the C version, we immediately return.
> + // We know the condition is met so we don't need to check again.
> + return Ok(val);
> + }
> + if let Some(timeout_delta) = timeout_delta {
> + if start.elapsed() > timeout_delta {
> + // Unlike the C version, we immediately return.
> + // We have just called `op()` so we don't need to call it again.
> + return Err(ETIMEDOUT);
> + }
> + }
> + if sleep {
> + fsleep(sleep_delta);
> + }
> + // fsleep() could be busy-wait loop so we always call cpu_relax().
> + cpu_relax();
> + }
> +}
>
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