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Message-ID: <CANpmjNOPiZ=h69V207AfcvWOB=Q+6QWzBKoKk1qTPVdfKsDQDw@mail.gmail.com>
Date: Thu, 20 Feb 2025 23:11:04 +0100
From: Marco Elver <elver@...gle.com>
To: paulmck@...nel.org
Cc: Alexander Potapenko <glider@...gle.com>, Bart Van Assche <bvanassche@....org>,
Bill Wendling <morbo@...gle.com>, Boqun Feng <boqun.feng@...il.com>,
Dmitry Vyukov <dvyukov@...gle.com>, Frederic Weisbecker <frederic@...nel.org>,
Greg Kroah-Hartman <gregkh@...uxfoundation.org>, Ingo Molnar <mingo@...nel.org>,
Jann Horn <jannh@...gle.com>, Joel Fernandes <joel@...lfernandes.org>,
Jonathan Corbet <corbet@....net>, Josh Triplett <josh@...htriplett.org>,
Justin Stitt <justinstitt@...gle.com>, Kees Cook <kees@...nel.org>,
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llvm@...ts.linux.dev, rcu@...r.kernel.org, linux-crypto@...r.kernel.org
Subject: Re: [PATCH RFC 15/24] rcu: Support Clang's capability analysis
On Thu, 20 Feb 2025 at 23:00, Paul E. McKenney <paulmck@...nel.org> wrote:
>
> On Thu, Feb 06, 2025 at 07:10:09PM +0100, Marco Elver wrote:
> > Improve the existing annotations to properly support Clang's capability
> > analysis.
> >
> > The old annotations distinguished between RCU, RCU_BH, and RCU_SCHED.
> > However, it does not make sense to acquire rcu_read_lock_bh() after
> > rcu_read_lock() - annotate the _bh() and _sched() variants to also
> > acquire 'RCU', so that Clang (and also Sparse) can warn about it.
>
> You lost me on this one. What breaks if rcu_read_lock_bh() is invoked
> while rcu_read_lock() is in effect?
I thought something like this does not make sense:
rcu_read_lock_bh();
..
rcu_read_lock();
..
rcu_read_unlock();
..
rcu_read_unlock_bh();
However, the inverse may well be something we might find somewhere in
the kernel?
Another problem was that if we want to indicate that "RCU" read lock
is held, then we should just be able to write
"__must_hold_shared(RCU)", and it shouldn't matter if rcu_read_lock()
or rcu_read_lock_bh() was used. Previously each of them acquired their
own capability "RCU" and "RCU_BH" respectively. But rather, we're
dealing with one acquiring a superset of the other, and expressing
that is also what I attempted to solve.
Let me rethink this...
Thanks,
-- Marco
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