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Message-ID: <20250304043223.68ed310f@pumpkin>
Date: Tue, 4 Mar 2025 04:32:23 +0000
From: David Laight <david.laight.linux@...il.com>
To: Bill Wendling <morbo@...gle.com>
Cc: "H. Peter Anvin" <hpa@...or.com>, Thomas Gleixner <tglx@...utronix.de>,
Ingo Molnar <mingo@...hat.com>, Borislav Petkov <bp@...en8.de>, Dave Hansen
<dave.hansen@...ux.intel.com>, "maintainer:X86 ARCHITECTURE (32-BIT AND
64-BIT)" <x86@...nel.org>, Eric Biggers <ebiggers@...nel.org>, Ard
Biesheuvel <ardb@...nel.org>, Nathan Chancellor <nathan@...nel.org>, Nick
Desaulniers <nick.desaulniers+lkml@...il.com>, Justin Stitt
<justinstitt@...gle.com>, LKML <linux-kernel@...r.kernel.org>,
linux-crypto@...r.kernel.org, clang-built-linux <llvm@...ts.linux.dev>
Subject: Re: [PATCH v2] x86/crc32: use builtins to improve code generation
On Mon, 3 Mar 2025 16:16:43 -0800
Bill Wendling <morbo@...gle.com> wrote:
> On Mon, Mar 3, 2025 at 3:58 PM H. Peter Anvin <hpa@...or.com> wrote:
> > On March 3, 2025 2:42:16 PM PST, David Laight <david.laight.linux@...il.com> wrote:
> > >On Mon, 3 Mar 2025 12:27:21 -0800
> > >Bill Wendling <morbo@...gle.com> wrote:
> > >
> > >> On Mon, Mar 3, 2025 at 12:15 PM David Laight
> > >> <david.laight.linux@...il.com> wrote:
> > >> > On Thu, 27 Feb 2025 15:47:03 -0800
> > >> > Bill Wendling <morbo@...gle.com> wrote:
> > >> >
> > >> > > For both gcc and clang, crc32 builtins generate better code than the
> > >> > > inline asm. GCC improves, removing unneeded "mov" instructions. Clang
> > >> > > does the same and unrolls the loops. GCC has no changes on i386, but
> > >> > > Clang's code generation is vastly improved, due to Clang's "rm"
> > >> > > constraint issue.
> > >> > >
> > >> > > The number of cycles improved by ~0.1% for GCC and ~1% for Clang, which
> > >> > > is expected because of the "rm" issue. However, Clang's performance is
> > >> > > better than GCC's by ~1.5%, most likely due to loop unrolling.
> > >> >
> > >> > How much does it unroll?
> > >> > How much you need depends on the latency of the crc32 instruction.
> > >> > The copy of Agner's tables I have gives it a latency of 3 on
> > >> > pretty much everything.
> > >> > If you can only do one chained crc instruction every three clocks
> > >> > it is hard to see how unrolling the loop will help.
> > >> > Intel cpu (since sandy bridge) will run a two clock loop.
> > >> > With three clocks to play with it should be easy (even for a compiler)
> > >> > to generate a loop with no extra clock stalls.
> > >> >
> > >> > Clearly if Clang decides to copy arguments to the stack an extra time
> > >> > that will kill things. But in this case you want the "m" constraint
> > >> > to directly read from the buffer (with a (reg,reg,8) addressing mode).
> > >> >
> > >> Below is what Clang generates with the builtins. From what Eric said,
> > >> this code is only run for sizes <= 512 bytes? So maybe it's not super
> > >> important to micro-optimize this. I apologize, but my ability to
> > >> measure clock loops for x86 code isn't great. (I'm sure I lack the
> > >> requisite benchmarks, etc.)
> > >
> > >Jeepers - that is trashing the I-cache.
> > >Not to mention all the conditional branches at the bottom.
> > >Consider the basic loop:
> > >1: crc32q (%rcx), %rbx
> > > addq $8, %rcx
> > > cmp %rcx, %rdx
> > > jne 1b
> > >The crc32 has latency 3 so it must take at least 3 clocks.
> > >Even naively the addq can be issued in the same clock as the crc32
> > >and the cmp and jne in the following ones.
> > >Since the jne is predicted taken, the addq can be assumed to execute
> > >in the same clock as the jne.
> > >(The cmp+jne might also get merged into a single u-op)
> > >(I've done this with adc (for IP checksum), with two adc the loop takes
> > >two clocks even with the extra memory reads.)
> > >
> > >So that loop is likely to run limited by the three clock latency of crc32.
> > >Even the memory reads will happen with all the crc32 just waiting for the
> > >previous crc32 to finish.
> > >You can take an instruction out of the loop:
> > >1: crc32q (%rcx,%rdx), %rbx
> > > addq $8, %rdx
> > > jne 1b
> > >but that may not be necessary, and (IIRC) gcc doesn't like letting you
> > >generate it.
> > >
> > >For buffers that aren't multiples of 8 bytes 'remember' that the crc of
> > >a byte depends on how far it is from the end of the buffer, and that initial
> > >zero bytes have no effect.
> > >So (provided the buffer is 8+ bytes long) read the first 8 bytes, shift
> > >right by the number of bytes needed to make the rest of the buffer a multiple
> > >or 8 bytes (the same as reading from across the start of the buffer and masking
> > >the low bytes) then treat exactly the same as a buffer that is a multiple
> > >of 8 bytes long.
> > >Don't worry about misaligned reads, you lose less than one clock per cache
> > >line (that is with adc doing a read every clock).
> > >
> For reference, GCC does much better with code gen, but only with the builtin:
>
> .L39:
> crc32q (%rax), %rbx # MEM[(long unsigned int *)p_40], tmp120
> addq $8, %rax #, p
> cmpq %rcx, %rax # _37, p
> jne .L39 #,
That looks reasonable, if Clang's 8 unrolled crc32q is faster per byte
then you either need to unroll once (no point doing any more) or use
the loop that does negative offsets from the end.
> leaq (%rsi,%rdi,8), %rsi #, p
That is gcc being brain-dead again.
It pretty much refuses to use a loop-updated pointer (%rax above)
and recalculates it from the count.
At least it is a single instruction here and there are the extra
register don't cause a spill to stack.
> .L38:
> andl $7, %edx #, len
> je .L41 #,
> addq %rsi, %rdx # p, _11
> movl %ebx, %eax # crc, <retval>
> .p2align 4
> .L40:
> crc32b (%rsi), %eax # MEM[(const u8 *)p_45], <retval>
> addq $1, %rsi #, p
> cmpq %rsi, %rdx # p, _11
> jne .L40 #,
>
> > >Actually measuring the performance is hard.
> > >You can use rdtsc because the clock speed will change when the cpu gets busy.
> > >There is a 'performance counter' that is actual clocks.
> > >While you can use the library functions to set it up, you need to just read the
> > >register - the library overhead it too big.
> > >You also need the odd lfence.
> > >Having done that, and provided the buffer is in the L1 d-cache you can measure
> > >the loop time in clocks and compare against the expected value.
> > >Once you've got 3 clocks per crc32 instruction it won't get any better,
> > >which is why the 'fast' code for big buffers does crc of 3+ buffers sections
> > >in parallel.
> > >
> Thanks for the info! It'll help a lot the next time I need to delve
> deeply into performance.
>
> I tried using rdtsc and another programmatic way of measuring timing.
> Also tried making the task have high priority, restricting to one CPU,
> etc. But the numbers weren't as consistent as I wanted them to be. The
> times I reported were the based on the fastest times / clocks /
> whatever from several runs for each build.
I'll find the code loop I use - machine isn't powered on at the moment.
>
> > > David
> > >
> > >>
> > >> -bw
> > >>
> > >> .LBB1_9: # =>This Inner Loop Header: Depth=1
> > >> movl %ebx, %ebx
> > >> crc32q (%rcx), %rbx
> > >> addq $8, %rcx
> > >> incq %rdi
> > >> cmpq %rdi, %rsi
> > >> jne .LBB1_9
> > >> # %bb.10:
> > >> subq %rdi, %rax
> > >> jmp .LBB1_11
> > >> .LBB1_7:
> > >> movq %r14, %rcx
> > >> .LBB1_11:
> > >> movq %r15, %rsi
> > >> andq $-8, %rsi
> > >> cmpq $7, %rdx
> > >> jb .LBB1_14
> > >> # %bb.12:
> > >> xorl %edx, %edx
> > >> .LBB1_13: # =>This Inner Loop Header: Depth=1
> > >> movl %ebx, %ebx
> > >> crc32q (%rcx,%rdx,8), %rbx
> > >> crc32q 8(%rcx,%rdx,8), %rbx
> > >> crc32q 16(%rcx,%rdx,8), %rbx
> > >> crc32q 24(%rcx,%rdx,8), %rbx
> > >> crc32q 32(%rcx,%rdx,8), %rbx
> > >> crc32q 40(%rcx,%rdx,8), %rbx
> > >> crc32q 48(%rcx,%rdx,8), %rbx
> > >> crc32q 56(%rcx,%rdx,8), %rbx
> > >> addq $8, %rdx
> > >> cmpq %rdx, %rax
> > >> jne .LBB1_13
> > >> .LBB1_14:
> > >> addq %rsi, %r14
> > >> .LBB1_15:
> > >> andq $7, %r15
> > >> je .LBB1_23
> > >> # %bb.16:
> > >> crc32b (%r14), %ebx
> > >> cmpl $1, %r15d
> > >> je .LBB1_23
> > >> # %bb.17:
> > >> crc32b 1(%r14), %ebx
> > >> cmpl $2, %r15d
> > >> je .LBB1_23
> > >> # %bb.18:
> > >> crc32b 2(%r14), %ebx
> > >> cmpl $3, %r15d
> > >> je .LBB1_23
> > >> # %bb.19:
> > >> crc32b 3(%r14), %ebx
> > >> cmpl $4, %r15d
> > >> je .LBB1_23
> > >> # %bb.20:
> > >> crc32b 4(%r14), %ebx
> > >> cmpl $5, %r15d
> > >> je .LBB1_23
> > >> # %bb.21:
> > >> crc32b 5(%r14), %ebx
> > >> cmpl $6, %r15d
> > >> je .LBB1_23
> > >> # %bb.22:
> > >> crc32b 6(%r14), %ebx
> > >> .LBB1_23:
> > >> movl %ebx, %eax
> > >> .LBB1_24:
> > >
> > >
> >
> > The tail is *weird*. Wouldn't it be better to do a 4-2-1 stepdown?
Well, provided the branches aren't mispredicted it'll be limited by
the crc32b - so three clocks per byte, max 27
The 4-2-1 stepdown needs the extra address update but that may not cost
and is then max 9 clocks. Also a lot less I-cache.
The code logic may not matter unless the buffer is short.
I think the cpu will be executing the tail instructions while many
of the crc32 from the main loop are still queued waiting results
from earlier instructions (especially if you get a loop that would
run in two clocks with (say) addq instead of crc32q.
> Definitely on the weird side! I considered hard-coding something like
> that, but thought it might be a bit convoluted, though certainly less
> convoluted than what we generate now. A simple loop is probably all
> that's needed, because it should only need to be done at most seven
> times.
The byte loop should be limited by the crc32b. So probably as fast
as that unrolled mess, although it will always have a mispredicted
branch (or two) - I suspect all loops do.
David
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