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Message-ID: <174108103121.14745.64964785500812681.tip-bot2@tip-bot2>
Date: Tue, 04 Mar 2025 09:37:11 -0000
From: "tip-bot2 for Ahmed S. Darwish" <tip-bot2@...utronix.de>
To: linux-tip-commits@...r.kernel.org
Cc: "Ahmed S. Darwish" <darwi@...utronix.de>, Ingo Molnar <mingo@...nel.org>,
stable@...nel.org, "H. Peter Anvin" <hpa@...or.com>,
Linus Torvalds <torvalds@...ux-foundation.org>, x86@...nel.org,
linux-kernel@...r.kernel.org
Subject: [tip: x86/urgent] x86/cpu: Validate CPUID leaf 0x2 EDX output
The following commit has been merged into the x86/urgent branch of tip:
Commit-ID: 1881148215c67151b146450fb89ec22fd92337a7
Gitweb: https://git.kernel.org/tip/1881148215c67151b146450fb89ec22fd92337a7
Author: Ahmed S. Darwish <darwi@...utronix.de>
AuthorDate: Tue, 04 Mar 2025 09:51:13 +01:00
Committer: Ingo Molnar <mingo@...nel.org>
CommitterDate: Tue, 04 Mar 2025 09:59:14 +01:00
x86/cpu: Validate CPUID leaf 0x2 EDX output
CPUID leaf 0x2 emits one-byte descriptors in its four output registers
EAX, EBX, ECX, and EDX. For these descriptors to be valid, the most
significant bit (MSB) of each register must be clear.
Leaf 0x2 parsing at intel.c only validated the MSBs of EAX, EBX, and
ECX, but left EDX unchecked.
Validate EDX's most-significant bit as well.
Fixes: e0ba94f14f74 ("x86/tlb_info: get last level TLB entry number of CPU")
Signed-off-by: Ahmed S. Darwish <darwi@...utronix.de>
Signed-off-by: Ingo Molnar <mingo@...nel.org>
Cc: stable@...nel.org
Cc: "H. Peter Anvin" <hpa@...or.com>
Cc: Linus Torvalds <torvalds@...ux-foundation.org>
Link: https://lore.kernel.org/r/20250304085152.51092-3-darwi@linutronix.de
---
arch/x86/kernel/cpu/intel.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/arch/x86/kernel/cpu/intel.c b/arch/x86/kernel/cpu/intel.c
index 3dce22f..2a3716a 100644
--- a/arch/x86/kernel/cpu/intel.c
+++ b/arch/x86/kernel/cpu/intel.c
@@ -799,7 +799,7 @@ static void intel_detect_tlb(struct cpuinfo_x86 *c)
cpuid(2, ®s[0], ®s[1], ®s[2], ®s[3]);
/* If bit 31 is set, this is an unknown format */
- for (j = 0 ; j < 3 ; j++)
+ for (j = 0 ; j < 4 ; j++)
if (regs[j] & (1 << 31))
regs[j] = 0;
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