linux-kernel - Re: [PATCH] Documentation: Add "Unaccepted" meminfo entry

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Message-ID: <e2807c0f-c6db-4946-a731-009d34c2c72e@redhat.com>
Date: Tue, 18 Mar 2025 09:42:31 +0100
From: David Hildenbrand <david@...hat.com>
To: Nico Pache <npache@...hat.com>, linux-kernel@...r.kernel.org,
 linux-fsdevel@...r.kernel.org, linux-doc@...r.kernel.org,
 kirill.shutemov@...ux.intel.com
Cc: corbet@....net, akpm@...ux-foundation.org, surenb@...gle.com,
 pasha.tatashin@...een.com, catalin.marinas@....com, jeffxu@...omium.org,
 andrii@...nel.org, xu.xin16@....com.cn
Subject: Re: [PATCH] Documentation: Add "Unaccepted" meminfo entry

On 18.03.25 00:04, Nico Pache wrote:
> Commit dcdfdd40fa82 ("mm: Add support for unaccepted memory") added a
> entry to meminfo but did not document it in the proc.rst file.
> 
> This counter tracks the amount of "Unaccepted" guest memory for some
> Virtual Machine platforms, such as Intel TDX or AMD SEV-SNP.
> 
> Add the missing entry in the documentation.
> 
> Signed-off-by: Nico Pache <npache@...hat.com>
> ---
>   Documentation/filesystems/proc.rst | 3 +++
>   1 file changed, 3 insertions(+)
> 
> diff --git a/Documentation/filesystems/proc.rst b/Documentation/filesystems/proc.rst
> index 09f0aed5a08b..8fcf19c31b18 100644
> --- a/Documentation/filesystems/proc.rst
> +++ b/Documentation/filesystems/proc.rst
> @@ -1060,6 +1060,7 @@ Example output. You may not have all of these fields.
>       FilePmdMapped:         0 kB
>       CmaTotal:              0 kB
>       CmaFree:               0 kB
> +    Unaccepted:            0 kB
>       HugePages_Total:       0
>       HugePages_Free:        0
>       HugePages_Rsvd:        0
> @@ -1228,6 +1229,8 @@ CmaTotal
>                 Memory reserved for the Contiguous Memory Allocator (CMA)
>   CmaFree
>                 Free remaining memory in the CMA reserves
> +Unaccepted
> +              Memory that has not been accepted by the guest

I was wondering if we could be clearer like

"Memory that has not been accepted. Especially in some confidential VM 
implementations, memory must be accepted manually by the guest OS before 
it can be used the first time."

In any case

Acked-by: David Hildenbrand <david@...hat.com>

-- 
Cheers,

David / dhildenb