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Message-ID: <20250523145942.GL39944@noisy.programming.kicks-ass.net>
Date: Fri, 23 May 2025 16:59:42 +0200
From: Peter Zijlstra <peterz@...radead.org>
To: Aaron Lu <ziqianlu@...edance.com>
Cc: Valentin Schneider <vschneid@...hat.com>,
Ben Segall <bsegall@...gle.com>,
K Prateek Nayak <kprateek.nayak@....com>,
Josh Don <joshdon@...gle.com>, Ingo Molnar <mingo@...hat.com>,
Vincent Guittot <vincent.guittot@...aro.org>,
Xi Wang <xii@...gle.com>, linux-kernel@...r.kernel.org,
Juri Lelli <juri.lelli@...hat.com>,
Dietmar Eggemann <dietmar.eggemann@....com>,
Steven Rostedt <rostedt@...dmis.org>, Mel Gorman <mgorman@...e.de>,
Chengming Zhou <chengming.zhou@...ux.dev>,
Chuyi Zhou <zhouchuyi@...edance.com>,
Jan Kiszka <jan.kiszka@...mens.com>,
Florian Bezdeka <florian.bezdeka@...mens.com>
Subject: Re: [PATCH 4/7] sched/fair: Take care of group/affinity/sched_class
change for throttled task
On Thu, May 22, 2025 at 08:49:43PM +0800, Aaron Lu wrote:
> On Thu, May 22, 2025 at 02:03:36PM +0200, Peter Zijlstra wrote:
> > This is asymmetric -- dequeue removes it from that throttle list, but
> > the corresponding enqueue will not add it back, what gives?
> >
> > Because now we have:
> >
> > p->on_rq=1
> > p->throttle_node on list
> >
> > move_queued_task()
> > deactivate_task()
> > dequeue_task_fair()
> > list_del_init(throttle_node)
> > p->on_rq = 2
> >
> > activate_task()
> > enqueue_task_fair()
> > // nothing special, makes the thing runnable
> > p->on_rq = 1;
> >
> > and we exit with a task that is on-rq and not throttled ?!?
> >
> > Why is this? Are we relying on pick_task_fair() to dequeue it again and
> > fix up our inconsistencies? If so, that had better have a comment on.
>
> Correct.
But would it not be better to have enqueue bail when we're trying to
enqueue an already throttled task into a throttled cfs_rq?
It seems a waste to do the actual enqueue, pick, dequeue when we
could've just avoided all that.
The immediate problem seems to be that you destroy the
task_is_throttled() state on dequeue, but surely that is trivially
fixable by not keeping that state in the list.
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