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Message-ID: <7eed2cf1-5d54-4669-9e31-96707a116f01@molgen.mpg.de>
Date: Tue, 27 May 2025 16:43:22 +0200
From: Paul Menzel <pmenzel@...gen.mpg.de>
To: Mikael Wessel <post@...aelkw.online>
Cc: netdev@...r.kernel.org, intel-wired-lan@...ts.osuosl.org,
torvalds@...uxfoundation.org, anthony.l.nguyen@...el.com,
przemyslaw.kitszel@...el.com, andrew@...n.ch, kuba@...nel.org,
pabeni@...hat.com, security@...nel.org, stable@...r.kernel.org,
davem@...emloft.net, edumazet@...gle.com, linux-kernel@...r.kernel.org
Subject: Re: [Intel-wired-lan] [PATCH v2 1/1] e1000e: fix heap overflow in
e1000_set_eeprom()
Dear Mikael,
Thank you for your patch.
Am 27.05.25 um 10:56 schrieb Mikael Wessel:
> The ETHTOOL_SETEEPROM ioctl copies user data into a kmalloc'ed buffer
> without validating eeprom->len and eeprom->offset. A CAP_NET_ADMIN
> user can overflow the heap and crash the kernel or gain code execution.
>
> Validate length and offset before memcpy().
>
> Fixes: bc7f75fa9788 ("[E1000E]: New pci-express e1000 driver (currently for ICH9 devices only)")
> Reported-by: Mikael Wessel <post@...aelkw.online>
> Signed-off-by: Mikael Wessel <post@...aelkw.online>
> Cc: stable@...r.kernel.org
> ---
> drivers/net/ethernet/intel/e1000e/ethtool.c | 3 +++
> 1 file changed, 3 insertions(+)
>
> diff --git a/drivers/net/ethernet/intel/e1000e/ethtool.c b/drivers/net/ethernet/intel/e1000e/ethtool.c
> index 9364bc2b4eb1..98e541e39730 100644
> --- a/drivers/net/ethernet/intel/e1000e/ethtool.c
> +++ b/drivers/net/ethernet/intel/e1000e/ethtool.c
> @@ -596,6 +596,9 @@ static int e1000_set_eeprom(struct net_device *netdev,
> for (i = 0; i < last_word - first_word + 1; i++)
> le16_to_cpus(&eeprom_buff[i]);
>
> + if (eeprom->len > max_len ||
> + eeprom->offset > max_len - eeprom->len)
> + return -EINVAL;
I think you used spaces instead of tabs for indentation. It’d be great
if you could fix this, and send v3 tomorrow. Running
`scripts/checkpatch.pl` with the patch as an argument, should catch
these things.
> memcpy(ptr, bytes, eeprom->len);
>
> for (i = 0; i < last_word - first_word + 1; i++)
Kind regards,
Paul
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