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Message-Id: 
 <175798621825.559370.16652026022818101575.git-patchwork-notify@kernel.org>
Date: Tue, 16 Sep 2025 01:30:18 +0000
From: patchwork-bot+netdevbpf@...nel.org
To: Matthieu Baerts (NGI0) <matttbe@...nel.org>
Cc: martineau@...nel.org, geliang@...nel.org, davem@...emloft.net,
 edumazet@...gle.com, kuba@...nel.org, pabeni@...hat.com, horms@...nel.org,
 donald.hunter@...il.com, fw@...len.de, kishen.maloor@...el.com,
 shuah@...nel.org, dmytro@...tyi.net, netdev@...r.kernel.org,
 mptcp@...ts.linux.dev, linux-kernel@...r.kernel.org,
 linux-kselftest@...r.kernel.org, marek@...udflare.com
Subject: Re: [PATCH net 0/5] mptcp: pm: nl: announce deny-join-id0 flag

Hello:

This series was applied to netdev/net.git (main)
by Jakub Kicinski <kuba@...nel.org>:

On Fri, 12 Sep 2025 14:52:19 +0200 you wrote:
> During the connection establishment, a peer can tell the other one that
> it cannot establish new subflows to the initial IP address and port by
> setting the 'C' flag [1]. Doing so makes sense when the sender is behind
> a strict NAT, operating behind a legacy Layer 4 load balancer, or using
> anycast IP address for example.
> 
> When this 'C' flag is set, the path-managers must then not try to
> establish new subflows to the other peer's initial IP address and port.
> The in-kernel PM has access to this info, but the userspace PM didn't,
> not letting the userspace daemon able to respect the RFC8684.
> 
> [...]

Here is the summary with links:
  - [net,1/5] mptcp: set remote_deny_join_id0 on SYN recv
    https://git.kernel.org/netdev/net/c/96939cec9940
  - [net,2/5] mptcp: pm: nl: announce deny-join-id0 flag
    https://git.kernel.org/netdev/net/c/2293c57484ae
  - [net,3/5] selftests: mptcp: userspace pm: validate deny-join-id0 flag
    https://git.kernel.org/netdev/net/c/24733e193a0d
  - [net,4/5] mptcp: tfo: record 'deny join id0' info
    https://git.kernel.org/netdev/net/c/92da495cb657
  - [net,5/5] selftests: mptcp: sockopt: fix error messages
    https://git.kernel.org/netdev/net/c/b86418beade1

You are awesome, thank you!
-- 
Deet-doot-dot, I am a bot.
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