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Message-ID: <609E7E01-33A6-4931-AC89-1F4B2944FB64@nvidia.com>
Date: Mon, 20 Oct 2025 15:15:34 -0400
From: Zi Yan <ziy@...dia.com>
To: Gregory Price <gourry@...rry.net>, David Hildenbrand <david@...hat.com>
Cc: linux-mm@...ck.org, linux-kernel@...r.kernel.org, kernel-team@...a.com,
akpm@...ux-foundation.org, vbabka@...e.cz, surenb@...gle.com,
mhocko@...e.com, jackmanb@...gle.com, hannes@...xchg.org
Subject: Re: [RFC PATCH] page_alloc: allow migration of smaller hugepages
during contig_alloc.
On 20 Oct 2025, at 13:41, Gregory Price wrote:
> On Mon, Oct 20, 2025 at 07:24:04PM +0200, David Hildenbrand wrote:
>> On 20.10.25 19:06, Gregory Price wrote:
>>
>> Do we really need the folio_hugetlb_migratable() check?
>> This code is completely racy.
>
> My thought was it's better to check if any *one* folio in the bunch is
> non-migratable, it's better to never even call compaction in the first
> place. But you're right, this is racy.
>
> In one race, the compaction code will just fail if this bit gets set
> between now and the isolate call in folio_isolate_hugetlb() - resulting
> in searching the next block anyway. So that seemed ok?
>
> In the other race, the bit becomes un-set and we skip a block that might
> otherwise be valid.
>
> I can drop this check, it's just an optimistic optimization anyway.
>
> I should also probably check CONFIG_ARCH_ENABLE_HUGEPAGE_MIGRATION here
> regardless, since we should skip compaction if migration isn't possible.
>
>>> folio_nr_pages() should be fine AFAIKT (no
>> VM_WARN_ON() etc), not sure about folio_test_hugetlb_migratable().
>
> will change, and will check/change based on above thoughts.
If it is racy, could folio_order() or folio_nr_pages() return a bogusly
large and cause a wrong result?
In isolate_migratepages_block(), compound_order(page) is used and checked
against MAX_PAGE_ORDER to avoid a bogus page order. I wonder if we should
use the same pattern here.
Basically, what is the right way of checking a folio order without lock?
Should we have a standardized helper function for that?
--
Best Regards,
Yan, Zi
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