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Message-Id: <DG9RY7Y4VMWB.2IL8Y6Z4P5IA8@etsalapatis.com>
Date: Sun, 08 Feb 2026 12:59:36 -0500
From: "Emil Tsalapatis" <emil@...alapatis.com>
To: "Andrea Righi" <arighi@...dia.com>
Cc: "Tejun Heo" <tj@...nel.org>, "David Vernet" <void@...ifault.com>,
"Changwoo Min" <changwoo@...lia.com>, "Kuba Piecuch" <jpiecuch@...gle.com>,
"Christian Loehle" <christian.loehle@....com>, "Daniel Hodges"
<hodgesd@...a.com>, <sched-ext@...ts.linux.dev>,
<linux-kernel@...r.kernel.org>
Subject: Re: [PATCH 2/2] selftests/sched_ext: Add test to validate
ops.dequeue() semantics
On Sun Feb 8, 2026 at 8:55 AM EST, Andrea Righi wrote:
> On Sun, Feb 08, 2026 at 11:26:13AM +0100, Andrea Righi wrote:
>> On Sun, Feb 08, 2026 at 10:02:41AM +0100, Andrea Righi wrote:
>> ...
>> > > >> > - From ops.select_cpu():
>> > > >> > - scenario 0 (local DSQ): tasks dispatched to the local DSQ bypass
>> > > >> > the BPF scheduler entirely; they never enter BPF custody, so
>> > > >> > ops.dequeue() is not called,
>> > > >> > - scenario 1 (global DSQ): tasks dispatched to SCX_DSQ_GLOBAL also
>> > > >> > bypass the BPF scheduler, like the local DSQ; ops.dequeue() is
>> > > >> > not called,
>> > > >> > - scenario 2 (user DSQ): tasks enter BPF scheduler custody with full
>> > > >> > enqueue/dequeue lifecycle tracking and state machine validation
>> > > >> > (expects 1:1 enqueue/dequeue pairing).
>> > > >>
>> > > >> Could you add a note here about why there's no equivalent to scenario 6?
>> > > >> The differentiating factor between that and scenario 2 (nonterminal queue) is
>> > > >> that scx_dsq_insert_commit() is called regardless of whether the queue is terminal.
>> > > >> And this makes sense since for non-DSQ queues the BPF scheduler can do its
>> > > >> own tracking of enqueue/dequeue (plus it does not make too much sense to
>> > > >> do BPF-internal enqueueing in select_cpu).
>> > > >>
>> > > >> What do you think? If the above makes sense, maybe we should spell it out
>> > > >> in the documentation too. Maybe also add it makes no sense to enqueue
>> > > >> in an internal BPF structure from select_cpu - the task is not yet
>> > > >> enqueued, and would have to go through enqueue anyway.
>> > > >
>> > > > Oh, I just didn't think about it, we can definitely add to ops.select_cpu()
>> > > > a scenario equivalent to scenario 6 (push task to the BPF queue).
>> > > >
>> > > > From a practical standpoint the benefits are questionable, but in the scope
>> > > > of the kselftest I think it makes sense to better validate the entire state
>> > > > machine in all cases. I'll add this scenario as well.
>> > > >
>> > >
>> > > That makes sense! Let's add it for completeness. Even if it doesn't make
>> > > sense right now that may change in the future. For example, if we end
>> > > up finding a good reason to add the task into an internal structure from
>> > > .select_cpu(), we may allow the task to be explicitly marked as being in
>> > > the BPF scheduler's custody from a kfunc. Right now we can't do that
>> > > from select_cpu() unless we direct dispatch IIUC.
>> >
>> > Ok, I'll send a new patch later with the new scenario included. It should
>> > work already (if done properly in the test case), I think we don't need to
>> > change anything in the kernel.
>>
>> Actually I take that back. The internal BPF queue from ops.select_cpu()
>> scenario is a bit tricky, because when we return from ops.select_cpu()
>> without p->scx.ddsp_dsq_id being set, we don't know if the scheduler added
>> the task to an internal BPF queue or simply did nothing.
>>
>> We need to add some special logic here, preferably without introducing
>> overhead just to handle this particular (really uncommon) case. I'll take a
>> look.
>
> The more I think about this, the more it feels wrong to consider a task as
> being "in BPF scheduler custody" if it is stored in a BPF internal data
> structure from ops.select_cpu().
>
> At the point where ops.select_cpu() runs, the task has not yet entered the
> BPF scheduler's queues. While it is technically possible to stash the task
> in some BPF-managed structure from there, doing so should not imply full
> scheduler custody.
>
> In particular, we should not trigger ops.dequeue(), because the task has
> not reached the "enqueue" stage of its lifecycle. ops.select_cpu() is
> effectively a pre-enqueue hook, primarily intended as a fast path to bypass
> the scheduler altogether. As such, triggering ops.dequeue() in this case
> would not make sense IMHO.
>
> I think it would make more sense to document this behavior explicitly and
> leave the kselftest as is.
>
> Thoughts?
I am going back and forth on this but I think the problem is that the enqueue()
and dequeue() BPF callbacks we have are not actually symmetrical?
1) ops.enqueue() is "sched-ext specific work for the scheduler core's enqueue
method". This is independent on whether the task ends up in BPF custody or not.
It could be in a terminal DSQ, a non-terminal DSQ, or a BPF data structure.
2) ops.dequeue() is "remove task from BPF custody". E.g., it is used by the
BPF scheduler to signal whether it should keep a task within its
internal tracking structures.
So the edge case of ops.select_cpu() placing the task in BPF custody is
currently valid. The way I see it, we have two choices in terms of
semantics:
1) ops.dequeue() must be the equivalent of ops.enqueue(). If the BPF
scheduler writer decides to place a task into BPF custody during the
ops.select_cpu() that's on them. ops.select_cpu() is supposed to be a
pure function providing a hint, anyway. Using it to place a task into
BPF is a bit of an abuse even if allowed.
2) We interpret ops.dequeue() to mean "dequeue from the BPF scheduler".
In that case we allow the edge case and interpret ops.dequeue() as "the
function that must be called to clear the NEEDS_DEQ/IN_BPF flag", not as
the complement of ops.enqueue(). In most cases both will be true, and in
the cases where not then it's up to the scheduler writer to understand
the nuance.
I think while 2) is cleaner, it is more involved and honestly kinda
speculative. However, I think it's fair game since once we settle on
the semantics it will be more difficult to change them. Which one do you
think makes more sense?
>
> Thanks,
> -Andrea
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