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Message-Id: <a599bc5062d557db46496f0d7c7886b0@kernel.crashing.org>
Date: Sun, 12 Aug 2007 07:53:58 +0200
From: Segher Boessenkool <segher@...nel.crashing.org>
To: schwidefsky@...ibm.com
Cc: wjiang@...ilience.com,
Linus Torvalds <torvalds@...ux-foundation.org>,
wensong@...ux-vs.org, heiko.carstens@...ibm.com,
linux-kernel@...r.kernel.org, ak@...e.de, cfriesen@...tel.com,
netdev@...r.kernel.org, horms@...ge.net.au,
akpm@...ux-foundation.org, Chuck Ebbert <cebbert@...hat.com>,
davem@...emloft.net, zlynx@....org, Chris Snook <csnook@...hat.com>
Subject: Re: [PATCH] make atomic_t volatile on all architectures
>> You'd have to use "+m".
>
> Yes, though I would use "=m" on the output list and "m" on the input
> list. The reason is that I've seen gcc fall on its face with an ICE on
> s390 due to "+m". The explanation I've got from our compiler people was
> quite esoteric, as far as I remember gcc splits "+m" to an input
> operand
> and an output operand. Now it can happen that the compiler chooses two
> different registers to access the same memory location. "+m" requires
> that the two memory references are identical which causes the ICE if
> they are not.
The problem is very nicely described here, last paragraph:
<http://gcc.gnu.org/ml/gcc-patches/2007-07/msg01816.html>
It's not a problem anymore in (very) recent GCC, although
that of course won't help you in the kernel (yet).
> I do not know if the current compilers still do this. Has
> anyone else seen this happen ?
In recent GCC, it's actually documented:
The ordinary output operands must be write-only; GCC will assume that
the values in these operands before the instruction are dead and need
not be generated. Extended asm supports input-output or read-write
operands. Use the constraint character `+' to indicate such an operand
and list it with the output operands. You should only use read-write
operands when the constraints for the operand (or the operand in which
only some of the bits are to be changed) allow a register.
Note that last line.
Segher
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