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Message-Id: <d36ec7799cfb43557770951c1cd57355@kernel.crashing.org>
Date: Wed, 15 Aug 2007 22:42:08 +0200
From: Segher Boessenkool <segher@...nel.crashing.org>
To: Satyam Sharma <satyam@...radead.org>
Cc: Christoph Lameter <clameter@....com>, heiko.carstens@...ibm.com,
horms@...ge.net.au, Stefan Richter <stefanr@...6.in-berlin.de>,
Linux Kernel Mailing List <linux-kernel@...r.kernel.org>,
"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>,
netdev@...r.kernel.org, ak@...e.de, cfriesen@...tel.com,
rpjday@...dspring.com, jesper.juhl@...il.com,
linux-arch@...r.kernel.org,
Andrew Morton <akpm@...ux-foundation.org>, zlynx@....org,
schwidefsky@...ibm.com, Chris Snook <csnook@...hat.com>,
Herbert Xu <herbert@...dor.apana.org.au>, davem@...emloft.net,
Linus Torvalds <torvalds@...ux-foundation.org>,
wensong@...ux-vs.org, wjiang@...ilience.com
Subject: Re: [PATCH 0/24] make atomic_read() behave consistently across all architectures
>> What volatile does are a) never optimise away a read (or write)
>> to the object, since the data can change in ways the compiler
>> cannot see; and b) never move stores to the object across a
>> sequence point. This does not mean other accesses cannot be
>> reordered wrt the volatile access.
>>
>> If the abstract machine would do an access to a volatile-
>> qualified object, the generated machine code will do that
>> access too. But, for example, it can still be optimised
>> away by the compiler, if it can prove it is allowed to.
>
> As (now) indicated above, I had meant multiple volatile accesses to
> the same object, obviously.
Yes, accesses to volatile objects are never reordered with
respect to each other.
> BTW:
>
> #define atomic_read(a) (*(volatile int *)&(a))
> #define atomic_set(a,i) (*(volatile int *)&(a) = (i))
>
> int a;
>
> void func(void)
> {
> int b;
>
> b = atomic_read(a);
> atomic_set(a, 20);
> b = atomic_read(a);
> }
>
> gives:
>
> func:
> pushl %ebp
> movl a, %eax
> movl %esp, %ebp
> movl $20, a
> movl a, %eax
> popl %ebp
> ret
>
> so the first atomic_read() wasn't optimized away.
Of course. It is executed by the abstract machine, so
it will be executed by the actual machine. On the other
hand, try
b = 0;
if (b)
b = atomic_read(a);
or similar.
Segher
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