netdev - Re: [BUG] before() integer overflow

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Message-ID: <OFD6FD9FE8.66BA8559-ON8825749C.00619B98-8825749C.00621A40@us.ibm.com>
Date:	Tue, 5 Aug 2008 10:51:32 -0700
From:	David Stevens <dlstevens@...ibm.com>
To:	Nicolas Bareil <nico@...ir.org>
Cc:	netdev@...r.kernel.org, netdev-owner@...r.kernel.org
Subject: Re: [BUG] before() integer overflow

netdev-owner@...r.kernel.org wrote on 08/05/2008 10:19:18 AM:

> 
> If seq1 = 0xffffff and seq2 = 0 (so seq1 > seq2), the difference is
> equal to 0xffffff, or -1 as a 32 bits signed number.

        In the sequence space, 0xffffffff is before 0 (by 1), so
before() should return true. In your example, you don't have enough
f's for it to be -1 as a signed number, so I'm assuming you mean
8 of them there. If you mean 6 f's, then the result is not -1, but the
positive number 0xffffff, which returns false.

                                                                +-DLS


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