netdev - Re: Connection tracking and vlan

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Date:	Fri, 30 Oct 2009 16:15:56 -0700
From:	ebiederm@...ssion.com (Eric W. Biederman)
To:	Adayadil Thomas <adayadil.thomas@...il.com>
Cc:	Eric Dumazet <eric.dumazet@...il.com>,
	Herbert Xu <herbert@...dor.apana.org.au>,
	netdev@...r.kernel.org, Patrick McHardy <kaber@...sh.net>
Subject: Re: Connection tracking and vlan

Adayadil Thomas <adayadil.thomas@...il.com> writes:

> On Fri, Oct 30, 2009 at 11:31 AM, Eric Dumazet <eric.dumazet@...il.com> wrote:
>
>> Very strange, this question about vlan looks like discussion we had
>> yesterday (or the day before...) about interfaces (versus packet defragmentation)
>>
>> "IP conntracking" is about IP, and [V]LAN doesnt matter at all at this protocol level.
>>
>> Same thing if you have two interfaces, eth0 & eth1 : IP conntrack tuples dont
>> include interface name/index
>
> I am concerned about the following situation -
>
> The linux device is configured as a bridge and is deployed between the
> trunk ports
> of 2 switches. In this situation the linux device will be seeing 802.1q packets
> with vlan headers specifying the vlanids.
>
> It is valid to have an environment where private IP addresses are duplicated
> on different virtual LANs. i.e. it is valid to have machine A (
> 10.10.10.1) talking to
> machine B (10.10.10.2) on vlan 1,
> and
> at the same time machine C ( 10.10.10.1) talking to machine D
> (10.10.10.2) on vlan 2.
>
> Since they are on different LANs (VLANs), there should not be any issues.
>
> Now when VLANs are shared across switches, the trunk port will sent
> 802.1q tagged
> packets between the switches. Imagine these packets when going through
> the linux bridge.
> The 802.1q header should identify the separate vlans by the vlan id.
>
> If ip_conntrack does not consider vlans, it is possible that all 5
> tuple are the same
> and thus affect the connection tracking.
>
> I hope I have described the scenario well. If not I can explain in a
> more detailed fashion.

Unless you have multiple network namespaces linux assumes all packets are
in the same ip space.  And 10.10.10.1 is the same machine no matter
which interface you talk to it on.

Eric
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