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Message-Id: <8a3a1b65eeecd18357ac0cc941f43df153d4f271.1273708027.git.inaky.perez-gonzalez@intel.com>
Date: Fri, 14 May 2010 14:45:18 -0700
From: Inaky Perez-Gonzalez <inaky@...ux.intel.com>
To: netdev@...r.kernel.org, wimax@...uxwimax.org
Cc: "Prasanna S. Panchamukhi" <prasannax.s.panchamukhi@...el.com>
Subject: [patch 2.6.35 19/25] wimax/i2400m: SDIO specific TX queue's minimum buffer room for new message
From: Prasanna S. Panchamukhi <prasannax.s.panchamukhi@...el.com>
This patch specifies the TX queue's minimum buffer room required to
accommodate one smallest SDIO payload.
Please refer the documentation in the code.
Signed-off-by: Prasanna S. Panchamukhi <prasannax.s.panchamukhi@...el.com>
---
drivers/net/wimax/i2400m/sdio.c | 7 +++++++
1 files changed, 7 insertions(+), 0 deletions(-)
diff --git a/drivers/net/wimax/i2400m/sdio.c b/drivers/net/wimax/i2400m/sdio.c
index 7632f80..9bfc26e 100644
--- a/drivers/net/wimax/i2400m/sdio.c
+++ b/drivers/net/wimax/i2400m/sdio.c
@@ -483,6 +483,13 @@ int i2400ms_probe(struct sdio_func *func,
sdio_set_drvdata(func, i2400ms);
i2400m->bus_tx_block_size = I2400MS_BLK_SIZE;
+ /*
+ * Room required in the TX queue for SDIO message to accommodate
+ * a smallest payload while allocating header space is 224 bytes,
+ * which is the smallest message size(the block size 256 bytes)
+ * minus the smallest message header size(32 bytes).
+ */
+ i2400m->bus_tx_room_min = I2400MS_BLK_SIZE - I2400M_PL_ALIGN * 2;
i2400m->bus_pl_size_max = I2400MS_PL_SIZE_MAX;
i2400m->bus_setup = i2400ms_bus_setup;
i2400m->bus_dev_start = i2400ms_bus_dev_start;
--
1.6.6.1
--
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