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Date:	Wed, 22 Jun 2011 09:48:00 -0700
From:	Joe Perches <joe@...ches.com>
To:	Sebastian Pöhn 
	<sebastian.belden@...glemail.com>
Cc:	Sebastian Pöhn <sebastian.poehn@...den.com>,
	Linux Netdev <netdev@...r.kernel.org>
Subject: Re: [PATCH] gianfar v5: implement nfc

On Wed, 2011-06-22 at 11:29 +0200, Sebastian Pöhn wrote:
> First of all thanks for the feedback. I know the fgar_swap_*bits
> function is a bit ugly. The problem with your suggestion is that it is
> necessary to swap a1<>a2 and b1<>b2 AT THE SAME TIME.

These swaps are done sequentially.
> Otherwise
> information the second swap is needing is swapped away by the first one.

How so?

> > swap_bits(temp_table->fe[new_first],
> >  temp_table->fe[old_first], 0xff80);
> > swap_bits(temp_table->fe[new_last],
> >  temp_table->fe[old_last], 0xff80);

new_first and old_first are swapped.
new_last and old_last are swapped.

> @@ -1356,10 +1356,13 @@ static void gfar_sort_mask_table(struct gfar_mask_entry *mask_table,
>  			new_first = mask_table[start].start + 1;
>  			new_last = mask_table[i - 1].end;

I'm a bit confused by this:

+		if (prev != mask_table[i].block) {
+			old_first = mask_table[start].start + 1;
+			old_last = mask_table[i - 1].end;

[no changes to start or i]

+			new_first = mask_table[start].start + 1;
+			new_last = mask_table[i - 1].end;
+
+			gfar_swap_ff80_bits(&temp_table->fe[new_first],
+					&temp_table->fe[old_first],
+					&temp_table->fe[new_last],
+					&temp_table->fe[old_last]);

Doesn't this just swap the same bits around twice?


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