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Message-ID: <54B44B10.7000009@gmail.com>
Date:	Mon, 12 Jan 2015 14:30:40 -0800
From:	John Fastabend <john.fastabend@...il.com>
To:	tgraf <tgraf@...g.ch>
CC:	netdev <netdev@...r.kernel.org>
Subject: nft_hash rhashtable question

Hi Thomas,

I'm looking at the rhashtable usage.

But as I read the nft_hash_destroy() its not clear to me how
rht_for_each_entry_safe() and  nft_hash_elem_destroy() keep everything
in sync.

Here is the code in question,

> static void nft_hash_destroy(const struct nft_set *set)
> {
>         struct rhashtable *priv = nft_set_priv(set);
>         const struct bucket_table *tbl;
>         struct nft_hash_elem *he;
>         struct rhash_head *pos, *next;
>         unsigned int i;
>
>         /* Stop an eventual async resizing */
>         priv->being_destroyed = true;
>         mutex_lock(&priv->mutex); <-- get the lock so we have single updater
>
>         tbl = rht_dereference(priv->tbl, priv);
>         for (i = 0; i < tbl->size; i++) {
>                 rht_for_each_entry_safe(he, pos, next, tbl, i, node)
>                         nft_hash_elem_destroy(set, he);              <-- does a kfree on he?
>         }
>         mutex_unlock(&priv->mutex); <-- release the lock
>
>         rhashtable_destroy(priv);
> }


Is it really safe to kfree 'he' without waiting a grace
period for any rcu readers to drop the reference?

I'm considering what happens if nft_hash_destroy runs in
parallel with nft_hash_lookup?

Thanks,
John


-- 
John Fastabend         Intel Corporation
--
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