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Message-ID: <568ff5ce-02ac-40f9-ccf7-fa00fb9c6b2a@synopsys.com>
Date: Thu, 9 Aug 2018 16:07:48 +0100
From: Jose Abreu <Jose.Abreu@...opsys.com>
To: Andrew Lunn <andrew@...n.ch>, Jose Abreu <Jose.Abreu@...opsys.com>
CC: "netdev@...r.kernel.org" <netdev@...r.kernel.org>
Subject: Re: C45 support and mdiobus_scan
Hi Andrew,
Thanks for your answer :)
On 09-08-2018 16:03, Andrew Lunn wrote:
> On Thu, Aug 09, 2018 at 02:54:11PM +0100, Jose Abreu wrote:
>> Hi All,
>>
>> I'm preparing to add support for 10G in stmmac and I noticed that
>> Generic 10G PHY needs C45 support. Digging through the
>> registration callbacks for phy that are used in stmmac I reached
>> to mdiobus_scan() and the following call:
>>
>> phydev = get_phy_device(bus, addr, false);
>>
>> The last parameter is "is_c45", and is always being set to false ...
>>
>> Does this mean that I can't use the Generic 10G PHY in stmmac? I
>> don't mind link being fixed for 10G for now.
> Hi Jose
>
> So far, all MACs which support 10G have used phy-handle to point to a
> PHY on am MDIO bus, and that PHY uses .compatible =
> "ethernet-phy-ieee802.3-c45". of_mdiobus_register() will then find the
> PHY and register it. You really should try to follow this, if you can.
>
>> (Notice I'm using a PCI based setup so no DT bindings can help me
>> for this).
> That is not necessarily true. Take a look at:
>
> arch/arm/boot/dts/imx6qdl-zii-rdu2.dtsi
>
> &pcie {
> pinctrl-names = "default";
> pinctrl-0 = <&pinctrl_pcie>;
> reset-gpio = <&gpio7 12 GPIO_ACTIVE_LOW>;
> status = "okay";
>
> host@0 {
> reg = <0 0 0 0 0>;
>
> #address-cells = <3>;
> #size-cells = <2>;
>
> i210: i210@0 {
> reg = <0 0 0 0 0>;
> };
> };
> };
>
> The PCIe core will look in the device tree and when it creates the
> platform device for the i210 on the pcie bus, it points
> pdev->dev.of_node at this node. So long as you are using a platform
> with DT, you can do this. I hope you are not using x86..
Yes I am :( Any possible solution for this?
I guess in ultimate case I will have to switch to ARM based setup.
Thanks and Best Regards,
Jose Miguel Abreu
>
> Andrew
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