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Message-ID: <20190612132352.7ee27bf3@cakuba.netronome.com>
Date: Wed, 12 Jun 2019 13:23:52 -0700
From: Jakub Kicinski <jakub.kicinski@...ronome.com>
To: Maxim Mikityanskiy <maximmi@...lanox.com>
Cc: Alexei Starovoitov <ast@...nel.org>,
Daniel Borkmann <daniel@...earbox.net>,
Björn Töpel <bjorn.topel@...el.com>,
Magnus Karlsson <magnus.karlsson@...el.com>,
"bpf@...r.kernel.org" <bpf@...r.kernel.org>,
"netdev@...r.kernel.org" <netdev@...r.kernel.org>,
"David S. Miller" <davem@...emloft.net>,
Saeed Mahameed <saeedm@...lanox.com>,
Jonathan Lemon <bsd@...com>,
Tariq Toukan <tariqt@...lanox.com>,
Martin KaFai Lau <kafai@...com>,
Song Liu <songliubraving@...com>, Yonghong Song <yhs@...com>,
Maciej Fijalkowski <maciejromanfijalkowski@...il.com>
Subject: Re: [PATCH bpf-next v4 07/17] libbpf: Support drivers with
non-combined channels
On Wed, 12 Jun 2019 15:56:48 +0000, Maxim Mikityanskiy wrote:
> Currently, libbpf uses the number of combined channels as the maximum
> queue number. However, the kernel has a different limitation:
>
> - xdp_reg_umem_at_qid() allows up to max(RX queues, TX queues).
>
> - ethtool_set_channels() checks for UMEMs in queues up to
> combined_count + max(rx_count, tx_count).
>
> libbpf shouldn't limit applications to a lower max queue number. Account
> for non-combined RX and TX channels when calculating the max queue
> number. Use the same formula that is used in ethtool.
>
> Signed-off-by: Maxim Mikityanskiy <maximmi@...lanox.com>
> Reviewed-by: Tariq Toukan <tariqt@...lanox.com>
> Acked-by: Saeed Mahameed <saeedm@...lanox.com>
I don't think this is correct. max_tx tells you how many TX channels
there can be, you can't add that to combined. Correct calculations is:
max_num_chans = max(max_combined, max(max_rx, max_tx))
> tools/lib/bpf/xsk.c | 6 +++---
> 1 file changed, 3 insertions(+), 3 deletions(-)
>
> diff --git a/tools/lib/bpf/xsk.c b/tools/lib/bpf/xsk.c
> index bf15a80a37c2..86107857e1f0 100644
> --- a/tools/lib/bpf/xsk.c
> +++ b/tools/lib/bpf/xsk.c
> @@ -334,13 +334,13 @@ static int xsk_get_max_queues(struct xsk_socket *xsk)
> goto out;
> }
>
> - if (channels.max_combined == 0 || errno == EOPNOTSUPP)
> + ret = channels.max_combined + max(channels.max_rx, channels.max_tx);
> +
> + if (ret == 0 || errno == EOPNOTSUPP)
> /* If the device says it has no channels, then all traffic
> * is sent to a single stream, so max queues = 1.
> */
> ret = 1;
> - else
> - ret = channels.max_combined;
>
> out:
> close(fd);
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