netdev - Re: [PATCH RFC/RFT 0/2] W=1 by default for Ethernet PHY subsystem

lists.openwall.net		lists / announce owl-users owl-dev john-users john-dev passwdqc-users yescrypt popa3d-users / oss-security kernel-hardening musl sabotage tlsify passwords / crypt-dev xvendor / Bugtraq Full-Disclosure linux-kernel linux-netdev linux-ext4 linux-hardening linux-cve-announce PHC
Open Source and information security mailing list archives

Hash Suite: Windows password security audit tool. GUI, reports in PDF.

[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]

Message-ID: <20210210183917.GA1471624@nvidia.com>
Date:   Wed, 10 Feb 2021 14:39:17 -0400
From:   Jason Gunthorpe <jgg@...dia.com>
To:     Andrew Lunn <andrew@...n.ch>, Nathan Chancellor <nathan@...nel.org>
CC:     Masahiro Yamada <masahiroy@...nel.org>,
        netdev <netdev@...r.kernel.org>,
        David Miller <davem@...emloft.net>,
        Jakub Kicinski <kuba@...nel.org>,
        "Michal Marek" <michal.lkml@...kovi.net>,
        Linux Kbuild mailing list <linux-kbuild@...r.kernel.org>,
        clang-built-linux <clang-built-linux@...glegroups.com>
Subject: Re: [PATCH RFC/RFT 0/2] W=1 by default for Ethernet PHY subsystem

On Sun, Sep 20, 2020 at 04:53:51PM +0200, Andrew Lunn wrote:

> How often are new W=1 flags added? My patch exported
> KBUILD_CFLAGS_WARN1. How about instead we export
> KBUILD_CFLAGS_WARN1_20200920. A subsystem can then sign up to being
> W=1 clean as for the 20200920 definition of W=1.

I think this is a reasonable idea.

I'm hitting exactly the issue this series is trying to solve, Lee
invested a lot of effort to make drivers/infiniband/ W=1 clean, but
as maintainer I can't sustain this since there is no easy way to have
a warning free compile and get all extra warnings.  Also all my
submitters are not running with W=1

I need kbuild to get everyone on the same page to be able to sustain
the warning clean up. We've already had a regression and it has only
been a few weeks :(

Andrew, would you consider respinning this series in the above form?

Thanks,
Jason