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Message-ID: <20221220083313.mj2fd4tvfoifayaq@sgarzare-redhat>
Date: Tue, 20 Dec 2022 09:33:13 +0100
From: Stefano Garzarella <sgarzare@...hat.com>
To: Arseniy Krasnov <AVKrasnov@...rdevices.ru>
Cc: Stefan Hajnoczi <stefanha@...hat.com>,
"edumazet@...gle.com" <edumazet@...gle.com>,
"David S. Miller" <davem@...emloft.net>,
Jakub Kicinski <kuba@...nel.org>,
Paolo Abeni <pabeni@...hat.com>,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
"netdev@...r.kernel.org" <netdev@...r.kernel.org>,
"virtualization@...ts.linux-foundation.org"
<virtualization@...ts.linux-foundation.org>,
"kvm@...r.kernel.org" <kvm@...r.kernel.org>,
kernel <kernel@...rdevices.ru>,
Krasnov Arseniy <oxffffaa@...il.com>
Subject: Re: [RFC PATCH v1 0/2] virtio/vsock: fix mutual rx/tx hungup
On Tue, Dec 20, 2022 at 07:14:27AM +0000, Arseniy Krasnov wrote:
>On 19.12.2022 18:41, Stefano Garzarella wrote:
>
>Hello!
>
>> Hi Arseniy,
>>
>> On Sat, Dec 17, 2022 at 8:42 PM Arseniy Krasnov <AVKrasnov@...rdevices.ru> wrote:
>>>
>>> Hello,
>>>
>>> seems I found strange thing(may be a bug) where sender('tx' later) and
>>> receiver('rx' later) could stuck forever. Potential fix is in the first
>>> patch, second patch contains reproducer, based on vsock test suite.
>>> Reproducer is simple: tx just sends data to rx by 'write() syscall, rx
>>> dequeues it using 'read()' syscall and uses 'poll()' for waiting. I run
>>> server in host and client in guest.
>>>
>>> rx side params:
>>> 1) SO_VM_SOCKETS_BUFFER_SIZE is 256Kb(e.g. default).
>>> 2) SO_RCVLOWAT is 128Kb.
>>>
>>> What happens in the reproducer step by step:
>>>
>>
>> I put the values of the variables involved to facilitate understanding:
>>
>> RX: buf_alloc = 256 KB; fwd_cnt = 0; last_fwd_cnt = 0;
>> free_space = buf_alloc - (fwd_cnt - last_fwd_cnt) = 256 KB
>>
>> The credit update is sent if
>> free_space < VIRTIO_VSOCK_MAX_PKT_BUF_SIZE [64 KB]
>>
>>> 1) tx tries to send 256Kb + 1 byte (in a single 'write()')
>>> 2) tx sends 256Kb, data reaches rx (rx_bytes == 256Kb)
>>> 3) tx waits for space in 'write()' to send last 1 byte
>>> 4) rx does poll(), (rx_bytes >= rcvlowat) 256Kb >= 128Kb, POLLIN is set
>>> 5) rx reads 64Kb, credit update is not sent due to *
>>
>> RX: buf_alloc = 256 KB; fwd_cnt = 64 KB; last_fwd_cnt = 0;
>> free_space = 192 KB
>>
>>> 6) rx does poll(), (rx_bytes >= rcvlowat) 192Kb >= 128Kb, POLLIN is set
>>> 7) rx reads 64Kb, credit update is not sent due to *
>>
>> RX: buf_alloc = 256 KB; fwd_cnt = 128 KB; last_fwd_cnt = 0;
>> free_space = 128 KB
>>
>>> 8) rx does poll(), (rx_bytes >= rcvlowat) 128Kb >= 128Kb, POLLIN is set
>>> 9) rx reads 64Kb, credit update is not sent due to *
>>
>> Right, (free_space < VIRTIO_VSOCK_MAX_PKT_BUF_SIZE) is still false.
>>
>> RX: buf_alloc = 256 KB; fwd_cnt = 196 KB; last_fwd_cnt = 0;
>> free_space = 64 KB
>>
>>> 10) rx does poll(), (rx_bytes < rcvlowat) 64Kb < 128Kb, rx waits in poll()
>>
>> I agree that the TX is stuck because we are not sending the credit
>> update, but also if RX sends the credit update at step 9, RX won't be
>> woken up at step 10, right?
>
>Yes, RX will sleep, but TX will wake up and as we inform TX how much
>free space we have, now there are two cases for TX:
>1) send "small" rest of data(e.g. without blocking again), leave 'write()'
> and continue execution. RX still waits in 'poll()'. Later TX will
> send enough data to wake up RX.
>2) send "big" rest of data - if rest is too big to leave 'write()' and TX
> will wait again for the free space - it will be able to send enough data
> to wake up RX as we compared 'rx_bytes' with rcvlowat value in RX.
Right, so I'd update the test to behave like this.
And I'd explain better the problem we are going to fix in the commit
message.
>>
>>>
>>> * is optimization in 'virtio_transport_stream_do_dequeue()' which
>>> sends OP_CREDIT_UPDATE only when we have not too much space -
>>> less than VIRTIO_VSOCK_MAX_PKT_BUF_SIZE.
>>>
>>> Now tx side waits for space inside write() and rx waits in poll() for
>>> 'rx_bytes' to reach SO_RCVLOWAT value. Both sides will wait forever. I
>>> think, possible fix is to send credit update not only when we have too
>>> small space, but also when number of bytes in receive queue is smaller
>>> than SO_RCVLOWAT thus not enough to wake up sleeping reader. I'm not
>>> sure about correctness of this idea, but anyway - I think that problem
>>> above exists. What do You think?
>>
>> I'm not sure, I have to think more about it, but if RX reads less
>> than
>> SO_RCVLOWAT, I expect it's normal to get to a case of stuck.
>>
>> In this case we are only unstucking TX, but even if it sends that single
>> byte, RX is still stuck and not consuming it, so it was useless to wake
>> up TX if RX won't consume it anyway, right?
>
>1) I think it is not useless, because we inform(not just wake up) TX that
>there is free space at RX side - as i mentioned above.
>2) Anyway i think that this situation is a little bit strange: TX thinks that
>there is no free space at RX and waits for it, but there is free space at RX!
>At the same time, RX waits in poll() forever - it is ready to get new portion
>of data to return POLLIN, but TX "thinks" exactly opposite thing - RX is full
>of data. Of course, if there will be just stalls in TX data handling - it will
>be ok - just performance degradation, but TX stucks forever.
We did it to avoid a lot of credit update messages.
Anyway I think here the main point is why RX is setting SO_RCVLOWAT to
128 KB and then reads only half of it?
So I think if the users set SO_RCVLOWAT to a value and then RX reads
less then it, is expected to get stuck.
Anyway, since the change will not impact the default behaviour
(SO_RCVLOWAT = 1) we can merge this patch, but IMHO we need to explain
the case better and improve the test.
>
>>
>> If RX woke up (e.g. SO_RCVLOWAT = 64KB) and read the remaining 64KB,
>> then it would still send the credit update even without this patch and
>> TX will send the 1 byte.
>
>But how RX will wake up in this case? E.g. it calls poll() without timeout,
>connection is established, RX ignores signal
RX will wake up because SO_RCVLOWAT is 64KB and there are 64 KB in the
buffer. Then RX will read it and send the credit update to TX because
free_space is 0.
Thanks,
Stefano
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