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Message-ID: <ZIDCpPbCFCxKBV2k@hoboy.vegasvil.org>
Date: Wed, 7 Jun 2023 10:47:16 -0700
From: Richard Cochran <richardcochran@...il.com>
To: Horatiu Vultur <horatiu.vultur@...rochip.com>
Cc: netdev@...r.kernel.org, linux-kernel@...r.kernel.org, andrew@...n.ch,
hkallweit1@...il.com, linux@...linux.org.uk, davem@...emloft.net,
edumazet@...gle.com, kuba@...nel.org, pabeni@...hat.com
Subject: Re: [PATCH net-next] net: micrel: Change to receive timestamp in the
frame for lan8841
On Wed, Jun 07, 2023 at 09:09:48AM +0200, Horatiu Vultur wrote:
> Doing these changes to start to get the received timestamp in the
> reserved field of the header, will give a great CPU usage performance.
> Running ptp4l with logSyncInterval of -9 will give a ~50% CPU
> improvment.
Really?
> -static struct lan8814_ptp_rx_ts *lan8841_ptp_get_rx_ts(struct kszphy_ptp_priv *ptp_priv)
> -{
> - struct phy_device *phydev = ptp_priv->phydev;
> - struct lan8814_ptp_rx_ts *rx_ts;
> - u32 sec, nsec;
> - u16 seq;
> -
> - nsec = phy_read_mmd(phydev, 2, LAN8841_PTP_RX_INGRESS_NS_HI);
> - if (!(nsec & LAN8841_PTP_RX_INGRESS_NSEC_HI_VALID))
> - return NULL;
> -
> - nsec = ((nsec & 0x3fff) << 16);
> - nsec = nsec | phy_read_mmd(phydev, 2, LAN8841_PTP_RX_INGRESS_NS_LO);
> -
> - sec = phy_read_mmd(phydev, 2, LAN8841_PTP_RX_INGRESS_SEC_HI);
> - sec = sec << 16;
> - sec = sec | phy_read_mmd(phydev, 2, LAN8841_PTP_RX_INGRESS_SEC_LO);
> -
> - seq = phy_read_mmd(phydev, 2, LAN8841_PTP_RX_MSG_HEADER2);
Before: 5x phy_read_mmd() per frame ...
> - rx_ts = kzalloc(sizeof(*rx_ts), GFP_KERNEL);
> - if (!rx_ts)
> - return NULL;
> -
> - rx_ts->seconds = sec;
> - rx_ts->nsec = nsec;
> - rx_ts->seq_id = seq;
> -
> - return rx_ts;
> -}
> +static void lan8841_ptp_getseconds(struct ptp_clock_info *ptp,
> + struct timespec64 *ts)
> +{
> + struct kszphy_ptp_priv *ptp_priv = container_of(ptp, struct kszphy_ptp_priv,
> + ptp_clock_info);
> + struct phy_device *phydev = ptp_priv->phydev;
> + time64_t s;
> +
> + mutex_lock(&ptp_priv->ptp_lock);
> + /* Issue the command to read the LTC */
> + phy_write_mmd(phydev, 2, LAN8841_PTP_CMD_CTL,
> + LAN8841_PTP_CMD_CTL_PTP_LTC_READ);
> +
> + /* Read the LTC */
> + s = phy_read_mmd(phydev, 2, LAN8841_PTP_LTC_RD_SEC_HI);
> + s <<= 16;
> + s |= phy_read_mmd(phydev, 2, LAN8841_PTP_LTC_RD_SEC_MID);
> + s <<= 16;
> + s |= phy_read_mmd(phydev, 2, LAN8841_PTP_LTC_RD_SEC_LO);
After: 4x phy_read_mmd() per frame. How does that save 50% cpu?
> + mutex_unlock(&ptp_priv->ptp_lock);
> +
> + set_normalized_timespec64(ts, s, 0);
> +}
> +static long lan8841_ptp_do_aux_work(struct ptp_clock_info *ptp)
> +{
> + struct kszphy_ptp_priv *ptp_priv = container_of(ptp, struct kszphy_ptp_priv,
> + ptp_clock_info);
> + struct skb_shared_hwtstamps *shhwtstamps;
> + struct timespec64 ts;
> + struct sk_buff *skb;
> + u32 ts_header;
> +
> + while ((skb = skb_dequeue(&ptp_priv->rx_queue)) != NULL) {
> + lan8841_ptp_getseconds(ptp, &ts);
No need to call this once per frame. It would be sufficent to call it
once every 2 seconds and cache the result.
> + ts_header = __be32_to_cpu(LAN8841_SKB_CB(skb)->header->reserved2);
> +
> + shhwtstamps = skb_hwtstamps(skb);
> + memset(shhwtstamps, 0, sizeof(*shhwtstamps));
> +
> + /* Check for any wrap arounds for the second part */
> + if ((ts.tv_sec & GENMASK(1, 0)) < ts_header >> 30)
> + ts.tv_sec -= GENMASK(1, 0) + 1;
> +
> + shhwtstamps->hwtstamp =
> + ktime_set((ts.tv_sec & ~(GENMASK(1, 0))) | ts_header >> 30,
> + ts_header & GENMASK(29, 0));
> + LAN8841_SKB_CB(skb)->header->reserved2 = 0;
> +
> + netif_rx(skb);
> + }
> +
> + return -1;
> +}
Thanks,
Richard
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